Answer:
The shaded shape on the grid is a rectangle. ...
Perimeter of the shaded shape = 3 + 4 + 3 + 4 = 14 units.
Area of the shaded shape = length × width.
Step-by-step explanation:
15% off means the sale price is 85% of the original price.
Divide the sale price by the percent of original price:
3825/0.85 = 4,500
answer : £4,500
Answer : The correct option is 
Step-by-step explanation :
According to the BODMAS rule, when the expression contains brackets open ((), {}, []) we have to first simplify the bracket followed by of (powers and roots etc.) and then we have to solve the division, multiplication, addition and subtraction from left to right order (respectively).
The given expression is:
![[\frac{(2a^{-3}b^4)^2}{(3a^5b)^{-2}}]^{-1}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%7B%283a%5E5b%29%5E%7B-2%7D%7D%5D%5E%7B-1%7D)
![=[\frac{(3a^5b)^{-2}}{(2a^{-3}b^4)^2}]^{1}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B%283a%5E5b%29%5E%7B-2%7D%7D%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%5D%5E%7B1%7D)
![=[\frac{1}{(3a^5b)^{2}}\times \frac{1}{(2a^{-3}b^4)^2}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B%283a%5E5b%29%5E%7B2%7D%7D%5Ctimes%20%5Cfrac%7B1%7D%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%5D)
![=[\frac{1}{9a^{10}b^2}\times \frac{1}{4a^{-6}b^8}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B9a%5E%7B10%7Db%5E2%7D%5Ctimes%20%5Cfrac%7B1%7D%7B4a%5E%7B-6%7Db%5E8%7D%5D)
![=[\frac{1}{9a^{10}b^2}\times \frac{a^6}{4b^8}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B9a%5E%7B10%7Db%5E2%7D%5Ctimes%20%5Cfrac%7Ba%5E6%7D%7B4b%5E8%7D%5D)

Thus, the given expression is equivalent to 
<span>0.0007 is the answer</span>
Answer:
(In Interval Notation:
)
Step-by-step explanation:
Given the following binomial:

You know that if this binomial is in the interval:

It must be:

Therefore, in order to find for what values of "x" the binomial
belongs to the given interval, you need to solve the inequality.
Then, you get:

Now, you can write this in Interval notation.
Since it is an Open Interval, you must use parentheses. Then, this is:
