Look at the picture &’ help.

A clothing store buys jeans for $12 and marks them up %200 before selling them to customers. What is the selling price of jeans?

zaharov [31]

I would multiply $12 times 200%

5 0

3 years ago

Complete 6,7 for 5 points.

seraphim [82]

Answer:

idk the answer

Step-by-step explanation:

4 0

3 years ago

The graph of which function has an axis of symmetry at x=3?

iragen [17]

Answer:

A graph that has an axis of symmetry at x = 3 would be x^2 -6x + 12

Step-by-step explanation:

In order to find a graph that has an axis of symmetry at 3, use the equation for the axis of symmetry of a quadratic.

x = -b/2a

In this equation, a is the coefficient of x^2 and b is the coefficient of x. So, if we use 3 as x and we choose a random number to be a (1), we can solve for the b.

3 = -b/2(1)

3 = -b/2

6 = -b

b = -6

Now that we have this, we can put those two numbers as coefficients. The constant at the end can be anything.

5 0

4 years ago

Read 2 more answers

Do you think my latest video on my Chanel I am looking for true advice that can help me learn from my mistakes and grow

neonofarm [45]

Answer: ching cheng hanji, hyong hyong chino, kitchen in the dungeon, iseweyata hong kong, hoo wata hachi, asalaminontlinto asalaminonto hong kong.

Step-by-step explanation:

4 0

2 years ago

Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o

Vikki [24]

Answer:

(a) The percent of her laps that are completed in less than 130 seconds is 55%.

(b) The fastest 3% of her laps are under 125.42 seconds.

(c) The middle 80% of her laps are from 126.80 seconds to 132.63 seconds.

Step-by-step explanation:

The random variable X is defined as the number of seconds for a randomly selected lap.

The random variable X is normally distributed with mean, μ = 129.71 seconds and standard deviation, σ = 2.28 seconds.

Thus, $X\sim N(129.71,\ 2.28^{2})$ .

(a)

Compute the probability that a lap is completes in less than 130 seconds as follows:

$P(X$

$=P(Z$

The percentage is, 0.55 × 100 = 55%.

Thus, the percent of her laps that are completed in less than 130 seconds is 55%.

(b)

Let x represents the 3rd percentile.

That is, P (X < x) = 0.03.

⇒ P (Z < z) = 0.03

The value of z for the above probability is:

z = -1.88

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\-1.88=\frac{x-129.71}{2.28}\\x=129.71-(1.88\times 2.28)\\x=125.4236\\x\approx 125.42$

Thus, the fastest 3% of her laps are under 125.42 seconds.

(c)

Let x₁ and x₂ be the values between which the middle 80% of the distribution lie.

That is,

$P(x_{1}$

The value of z for the above probability is:

z = 1.28

Compute the values of x₁ and x₂ as follows:

$-z=\frac{x_{1}-\mu}{\sigma}\\-1.28=\frac{x_{1}-129.71}{2.28}\\x_{1}=129.71-(1.28\times 2.28)\\x=126.7916\\x\approx 126.80$ $z=\frac{x_{2}-\mu}{\sigma}\\1.28=\frac{x_{2}-129.71}{2.28}\\x_{2}=129.71+(1.28\times 2.28)\\x=132.6284\\x\approx 132.63$

Thus, the middle 80% of her laps are from 126.80 seconds to 132.63 seconds.

5 0

4 years ago