Answer:
polar bear bc who doesnt want a polar bear in theyre room B)
Step-by-step explanation:
polr bears r cool
Answer:
3 toppings is the answer
Step-by-step explanation:
Answers: b, d and e
b.The graph has a relative minimum
d. The graph has an x intercept at 3,0
e. the graph has an y intercept at 0,-15
f(x)=(x+5)(x-3)
The given equation is in the form of f(x) = a(x-b)(x-c)
If 'a' is positive then graph has a relative minimum
If 'a' is negative then graph has a relative maximum
Here a=1 that is positive so graph has a relative minimum .
To find x intercept we set f(x) =0 and solve for x
0=(x+5)(x-3)
x+5 =0 -> x = -5 so x intercept is (-5,0)
x - 3=0 -> x= 3 so x intercept is (3,0)
To find y intercept we plug in 0 for x
y=(x+5)(x-3)
y=(0+5)(0-3) = -15
so y intercept is (0,-15)
All right...before we begin, let's lay some ground rules about the postulate your teacher asks for in every problem. <em>If you already know what they are, skip this paragraph...</em>
A postulate is a statement that claims how the triangles are congruent from looking at the paper. For example, on number 2 we have three sides of the triangle so we would use the postulate SSS (side, side, side). However, number one we would use SAS (side, angle, side) because we see the angle square showing it is a 90-degree angle.
Let's begin! (I haven't done triangles in a while so I apologize in advance if some of my answers might be incorrect on the congruent (yes or no) part of it.)
1.
A) From a visual perspective, we can see the triangles are congruent.
B) ABE = CDE because they are the corresponding points.
C) We can use SAS for the postulate.
2.
A) Yes, they are congruent.
B) OLE = OVE
C) We can use SSS for their postulate.
3.
A) Yes, they are congruent.
B) AWT = ERT
C) We can use SAS for the postulate.
4.
A) I believe the triangles are congruent. You might want to check me on that.
B) GFE = FGH
C) SSS
5.
A) They are congruent because if IH bisects it, it is directly in the middle. So, we know that WH = HS and IH = IH (duh.) and their angles match.
B) WHI = SHI
C) SAS
6.
A) This one is intriguing because it would state above the shape "LE bisects LGUE." I'm going to take that it isn't exactly in the middle, but I am still going to say it is congruent.
B) LGE = EUL
C) ASA
7.
A) Yes, they are definitely congruent.
B) RTU = TRS
C) SSS (We have nothing that indicates angles.)
8.
A) Yes, they are congruent.
B) YWV = VZY
C) We can use SAS. (Might want to check that one.)
9.
A) I would say this one is NOT congruent.
B) There are only two points. One way is HT = MA
C) They are not congruent, you can not use a postulate. However, if you teacher insists on putting one, I would use SAS.
Once again, I would be careful about my answers. I haven't worked with triangles in a few years. If my math is incorrect, or I didn't give the answer you were looking for, please let me know. However, if my math is on point, please consider marking as <em>Brainliest</em>.
Have a good one.
God Bless.
One thing to bear in mind with trigonometric expressions is that, the exponent location is next to the function name, instead of the whole expression, though it applies to the whole thing, namely cos²(x), is really [ cos(x) ]², and that matters for using the chain rule.
![\bf y=cos^2(x)-sin^2(x)\implies y=[cos(x)]^2-[sin(x)]^2 \\\\\\ \cfrac{dy}{dx}=\stackrel{chain~rule}{2cos(x)\cdot -sin(x)}~~-~~\stackrel{chain~rule}{2sin(x)\cdot cos(x)} \\\\\\ \cfrac{dy}{dx}=-2cos(x)sin(x)-2cos(x)sin(x) \\\\\\ \cfrac{dy}{dx}=-4cos(x)sin(x)](https://tex.z-dn.net/?f=%5Cbf%20y%3Dcos%5E2%28x%29-sin%5E2%28x%29%5Cimplies%20y%3D%5Bcos%28x%29%5D%5E2-%5Bsin%28x%29%5D%5E2%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7Bdy%7D%7Bdx%7D%3D%5Cstackrel%7Bchain~rule%7D%7B2cos%28x%29%5Ccdot%20-sin%28x%29%7D~~-~~%5Cstackrel%7Bchain~rule%7D%7B2sin%28x%29%5Ccdot%20cos%28x%29%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7Bdy%7D%7Bdx%7D%3D-2cos%28x%29sin%28x%29-2cos%28x%29sin%28x%29%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7Bdy%7D%7Bdx%7D%3D-4cos%28x%29sin%28x%29)
