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vlabodo [156]
2 years ago
5

2.3. Use the following subtraction strategies to calculate 884-597: 2.3.1. breaking up the second number 2.3.2. adding on to the

smaller number until you reach the bigger number 2.4. Design a real life activity for the Intermediate Phase in which learners will be required to apply the associative property of multiplication over addition. (4) (3) (3) 2.5. Suppose you want to have the activity in 2.4 marked by peers. Give a marking guideline according to which learners can score each other's work. (2) 2.6. Draw a diagram by which you can visually explain to learners in the Intermediate Phase why the sum of five consecutive numbers is equal to the fifth multiple of the middle number. Choose any set of five consecutive numbers to illustrate your statement. Write down your explanation in four powerful sentences. (5) OW a 2.3 . Use the following subtraction strategies to calculate 884-597 : 2.3.1 . breaking up the second number 2.3.2 . adding on to the smaller number until you reach the bigger number 2.4 . Design a real life activity for the Intermediate Phase in which learners will be required to apply the associative property of multiplication over addition . ( 4 ) ( 3 ) ( 3 ) 2.5 . Suppose you want to have the activity in 2.4 marked by peers . Give a marking guideline according to which learners can score each other's work . ( 2 ) 2.6 . Draw a diagram by which you can visually explain to learners in the Intermediate Phase why the sum of five consecutive numbers is equal to the fifth multiple of the middle number . Choose any set of five consecutive numbers to illustrate your statement . Write down your explanation in four powerful sentences . ( 5 ) OW a​
Mathematics
1 answer:
DochEvi [55]2 years ago
4 0

It should be noted that the value of 597 subtracted from 884 is 287.

<h3>How to illustrate the subtraction?</h3>

The information is simply that we should subtract 884 and 597 and also illustrate it.

This will be:

884 - 597 = 287.

A word problem illustrating this is that a man had 884 pens and gave 597 pens to his friends. How many pens does he have left?

This will be:

= 884 - 597 = 287

Learn more about subtraction on:

brainly.com/question/220101

#SPJ1

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\frac{x(x-4)}{(x+9)(x-4)}

Notice there's an (x-4) on both top and bottom. So they cancel out. That leaves us with your answer of \frac{x}{(x+9)}

#3. We do the same thing as above then multiply and simplify. In the interest of space, I'll cut straight to some simplification. 

\frac{2(x+2)^{3} }{6x(x+2)} ( \frac{5}{(x-2)^{2} } )

Now we start cancelling. For the first fraction, there are 3 (x+2)'s on top and 1 on the bottom so we will cancel out the one on the bottom and leave 2 (x+2)'s on top. There are no more polynomials to cancel out so now we multiply across:

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10 and 6 share a GCF of 2 so we divide both of those by 2. This leaves us with the final answer of:

\frac{5(x+2)^{2} }{3x(x-2)^{2} }

#4. This equation introduces division and because of it, we must flip the second fraction to make the division sign into a multiplication symbol. Again for space, I'll flip the fraction and simplify in one step. 

\frac{3(x+2)(x-2)}{(x+4)(x-2)} ( \frac{x+4}{6(x+3)})

Now we do our cancelling. First fraction has (x - 2) in the top and bottom. They're gone. The first fraction has a (x + 4) on the bottom and the second fraction has one on the top. Those will also cancel. This leaves you with:

\frac{3(x+2)}{6(x+3)}

3 and 6 share a GCF of 3 so we divide both numbers by this. This leaves you with your final answer:

\frac{x+2}{2(x+3)}

#5. We are adding so we first factor both fractions and see what we need to multiply by to make the denominators the same. I'll do the former first. (10 - x) and (x - 10) are not the same so we multiply the first equation (top and bottom) by (x - 10) and the second equation by (10 - x). Because they will now have the same denominator we can combine them already. This gives us:

\frac{(3+2x)(x-10)+(13+x)(10-x)}{(10-x)(x-10)}

Now we FOIL each to expand and then simplify by combining like terms. Again for space, I'm just showing the result of this; you end up with:

\frac{x^{2}-20x+100}{(10-x)(x-10)}

Now we factor the top. This gives you 2 (x - 10)'s on top and one on bottom. So we just leave one on the top and cancel the bottom one out. This leaves you with your answer:

\frac{x+10}{10-x}

#6. Same process for this one so I won't repeat. I'll just show the work.

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\frac{5x - 2}{(x-3)(x+2)(x-2)}

#7. For this question we find the least common denominator to make the denominators match. For 5, x, and 2x, the LCD is 10x. So we multiply top and bottom of each fraction by what would make the bottom equal 10x. This rewrites the fraction as:

\frac{3x}{5} ( \frac{2x}{2x}) * ( \frac{5}{x}( \frac{10}{10}) -  \frac{5}{2x} ( \frac{5}{5}))

Simplify to get:

\frac{3x}{5}  * ( \frac{25}{10x})

After simplifying again, you end up with your final answer: 

\frac{3}{2}




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