F(1) = 2
f(2) = -5f(2-1) = -5f(1) = -5(2) = -10
f(3) = -5f(3-1) = -5f(2) = -5(-10) = 50
So, f(4) = ?
<u>ANSWER</u>: 110
<u>EXPLANATION</u>:
Let these five numbers be a, b, c, d and e.
Then "<span>arithmetic means of 5 numbers is 100" implies
(a + b + c + d + e) / 5 = 100
>> a + b + c + d + e = 500
</span>And "arithmetic means of 2 of these numbers (suppose a and b) is 85" implies
(a + b) / 2 = 85
>> a + b = 170
Using these two equations, we have
(a + b) + c + d + e = 500
>> (170) + c + d + e = 500
>> c + d + e = 500 - 170
>> c + d + e = 330
So "t<span>he mean of the other 3 numbers (c,d and e)" is
</span>(c + d + e) / 3 = 330 / 3 = 110
Answer:
hope this helps you in some way
Answer: The place value of zero in any number is always zero. Zero may hold any place in a number, but its value will remain to be zero. In numbers having zeros such as 105, 350, 42017, 90218, the place value of 0 in each number is 0.