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Reil [10]
3 years ago
7

I need help with 5 and 14 pls

Mathematics
1 answer:
Julli [10]3 years ago
4 0

Answer:

5

(3a²b³c)³(2a⁴b²c²)³

= (3a⁶b⁹c³)(8a¹²b⁶c⁶)

= 24a¹⁸b¹⁵c⁹

14

⁴√(81a¹⁶b¹²c⁹)

= (⁴√81)(⁴√a¹⁶)(⁴√b¹²)(⁴√c⁹)

= 3 (a^{\frac{16}{4} }) (b^{\frac{12}{4} } ) (c^{\frac{9}{4} } )

= 3a^{4} b^{3} c^{\frac{9}{4} }

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alex41 [277]

Answer:

Where is the image

Step-by-step explanation:

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How do you find the quadratic equation of a parabola with the vertex and x intercept?
o-na [289]
This is the notes to finding the parabola

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whats the lateral area of a right circular cone if the diameter of the base is 4m and the slant height of the cone is 15m? round
alex41 [277]
First is to understand the terms. Lateral area is the surface area of a 3D figure, excluding the area of any base. 
<span>Laterial Area (L.A.) of a right cone = pi*radius*slant height </span>
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8 0
3 years ago
Simply.<br><br> -2/5 + 4/3<br><br> Show work.
mixer [17]

Answer:

14/15

Step-by-step explanation:

Find common denominators. Note that what you do to the denominator, you do to the numerator.

Use 15 as the common denominator:

(-2/5)(3/3) = (-6/15)

(4/3)(5/5) = (20/15)

Combine like terms:

-6/15 + 20/15 = (20 - 6)/15 = 14/15

14/15 is your answer.

~

8 0
2 years ago
Read 2 more answers
ANYONE GOOD AT MATH NEED HELP
lesantik [10]

Answer:

*I just learned that in probability if a question has 'and' it means you multiply and if it has 'or' it means you add*

1a) 1/6

There are two numbers greater than four (5 and 6). There are 6 possible numbers you can get, so the fraction would be 2/6, or simplified would be <u>1/3</u>. There are two options you can get when flipping a coin, so the chance of getting a head is <u>1/2</u>. This is an 'and' problem so multiply 1/3•1/2 and you get 1/6.

1b) 1/4

There are 3 even numbers (2, 4, and 6), so the probability would be 3/6 or simplified to <u>1/2</u>. The chance of landing on a tail is also <u>1/2</u>, as there are two possible options. This is an 'and' problem so multiply 1/2•1/2 and you get 1/4.

2) 1/8

Write out your possible results: HHH, HHT, HTH, THH, HTT, THT, TTH, TTT.

3a) 1/8

There are 4 shirt options to choose from. The chance of picking blue is <u>1/4</u>. There are 2 pant options. The chance of picking black is <u>1/2</u>. This is an 'and' problem, so multiply 1/4•1/2 and you get 1/8.

3b) 1/4

There are 4 shirt options to choose from. This is an 'or' problem because he can choose an orange shirt OR a red shirt. The probability of picking an orange shirt is 1/4 and the probability of picking a red shirt is 1/4. 'Or' means you use addition so add 1/4+1/4 and you get 2/4 or simplified is <u>1/2</u>. There are 2 pant options to choose from, so the probability of choosing brown pants is 1/2. Now, this is an 'and' problem, so multiply 1/2•1/2 and you get 1/4.

6 0
2 years ago
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