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topjm [15]
3 years ago
7

Write the slope-intercept form of the line that passes through (-10,17) and (5,-4)

Mathematics
1 answer:
luda_lava [24]3 years ago
3 0

Answer:

y = 7/5 x + 31

Step-by-step explanation:

To find the slope, we need to use the formula

m = (y2-y1)/(x2-x1)

m =(-4-17)/(5- -10)

   = -21/(5+10)

  = 21/15

Divide the top and bottom by 3.

  = 7/5

The slope is 7/5.


Using the point slope form of the equation,

y-y1 = m(x-x1)

y-17 = 7/5 (x--10)

y-17 = 7/5(x+10)

Distribute the 7/5 ths.

y-17 = 7/5 x + 7/5*10

y-17 = 7/5 x +14

Add 17 to each side

y = 7/5 x + 14 + 17

y = 7/5 x + 31


This is in slope intercept form, with the slope  being 7/5 and the y intercept of 31

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Answer:

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<em />

Step-by-step explanation:

Assume the hypotenuse of the triangle is c (c>0)

As the triangle inscribed in the semi circle is the right angle triangle, its hypotenuse is equal to the diameter of the circle.

The hypotenuse of the triangle can be calculated by Pythagoras theorem as following: c^{2} =a^{2} +b^{2} =(2\sqrt{5}) ^{2} + (4\sqrt{5}) ^{2} = 20 + 80 = 100

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So that the semi circle has the diameter = 10 => its radius = 5

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    => The total area of 2 semi circles is: \pi x 5^{2} = 25\pi

  • The area of a triangle inscribed in the semi circle is: 1/2 x a x b = 1/2 x 2\sqrt{5\\ x 4\sqrt{5} = 20

    => The area of 2 triangles inscribed in 2 semi circles is: 2 x 20 = 40

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<em>The area of the shaded part = The area of the square - The total area of 2 semi circles + The total are of 2 triangles inscribed in semi circles </em>

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