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CaHeK987 [17]
3 years ago
9

What is the surface area of a rectangle prism

Mathematics
2 answers:
Darina [25.2K]3 years ago
7 0
I think the answer is 40 because the rectangles each have a surface area of 8 and 8 times 4 is 32 then the squares have a surface area of 4 and 4 times 2 is 8 and 32+8 gives you the total surface area of 40
Debora [2.8K]3 years ago
5 0
Pretty sure it’s 48
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What is the length of leg y of the right triangle?<br> 84<br> 85<br> O1<br> 09<br> O 13<br> O 26
Softa [21]

Answer:

\boxed{\sf Length \ of \ leg \ y = 13}

Step-by-step explanation:

Pythagoras theorem states that <em>“In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides”</em>.

\therefore  \\  \sf \implies {84}^{2}  +  {y}^{2}  =  {85}^{2} \\  \\   \sf {84}^{2}  = 7056 : \\   \sf \implies 7056 +  {y}^{2}  =  {85}^{2} \\  \\   \sf {85}^{2}  = 7225 :  \\  \sf \implies 7056 +  {y}^{2}  = 7225 \\  \\  \sf Substract \:  7056 \:  from \:  both \:  sides : \\  \sf \implies (7056 - 7056) +  {y}^{2}  = 7225 - 7056  \\  \\  \sf 7056 - 7056 = 0 : \\   \sf \implies {y}^{2}  = 7225 - 7056 \\  \\  \sf 7225 - 7056 = 169 : \\   \sf \implies {y}^{2}  = 169 \\  \\  \sf 169 =  {13}^{2}  :  \\  \sf \implies {y}^{2}  =  {13}^{2}  \\  \\  \sf \implies y =  \sqrt{ {13}^{2} }  \\  \\  \sf \implies y =   {13}^{ \cancel{2} \times  \frac{1}{ \cancel{2}} }  \\  \\  \sf \implies y =  13

So,

Length of leg y of the right triangle = 13

5 0
3 years ago
Read 2 more answers
Find x and y in the parallelogram
REY [17]
X=7
Y=14

4x=28
X=7
2y=28
Y=14
7 0
4 years ago
Solve for the value of y in the triangle below.
german

Answer:

d

Step-by-step explanation:

6 0
3 years ago
Can 2x + 3y be simplified?
Wewaii [24]

Answer:

no

Step-by-step explanation:

4 0
3 years ago
For each ordered pair, determine whether it is a solution to y=-5x+2.
Sedbober [7]

There are two ways to do this.

The first is you plug in the x-value from the point in the table and see if that gives you the y-value from the same point.

For example, your first point is (5,49), so plug in x=5:

   y = -5(5)+2 = -25+2 = -23

Since that's not the y-value in (5,49), then (5,49) is not a solution for the equation.

The other option is you plug in both the x-value and the y-value to see if you get a true statement.  (A solution will make the equaiton a true statement.)

For example, the first point is (5,49), so you'd plug in x=5 and y=49:

    49 = -5(5)+2

    49 = -25 + 2

    49 = -23

Since that's not true, (5,49) is not a solution.

You'll notice you're basically doing the same thing, it's just whether you plug in one value or both and that's your choice.

8 0
3 years ago
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