The <u>correct answer</u> is:
A) The medians are both between 10 and 14 emails.
Explanation:
The <u>mode </u>is the easiest measure to find of a data set.
The <u>mode </u>of a data set is the data value that appears the most often. In plot A, there are 3 dots at 10 and 3 dots at 15; this means the modes are 10 and 15.
In plot B, there are 3 dots at 5 and 3 dots at 15; this means the modes are 5 and 15.
They <u>do not have the same modes</u>.
The <u>median </u>of a data set is the middle value. There are 10 dots in each dot plot; this means the medians will each be between two data points.
For plot A, we can see that the middle value is between 10 and 15.
For plot B, we can see that the middle value is between 10 and 15.
This means that choice A is correct, the medians of both are between 10 and 14.
Answer:
12
Step-by-step explanation:
Listing the weeks he will attend each item
Class 4,8,12,16
Chess 2,4,6,8,10,12
Fencing 3,6,9,12
Starting today at week 0, he will attend all 3 again at week 12
<u>We are given the equation:</u>
(a + b)! = a! + b!
<u>Testing the given equation</u>
In order to test it, we will let: a = 2 and b = 3
So, we can rewrite the equation as:
(2+3)! = 2! + 3!
5! = 2! + 3!
<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>
120 = 2 + 6
We can see that LHS ≠ RHS,
So, we can say that the given equation is incorrect
Answer:O_O
Step-by-step explanation:
Answer:
There may be 1 or 3 tricycles in the parking lot.
Step-by-step explanation:
Since at any point in time, there could be bicycles, tricycles, and cars in the school parking lot, and today, there are 53 wheels in total, if there are 15 bicycles, tricycles, and cars in total, to determine how many tricycles could be in the parking lot, the following calculation must be performed:
13 x 4 + 1 x 3 + 1 x 2 = 57
11 x 4 + 1 x 3 + 3 x 2 = 53
10 x 4 + 3 x 3 + 2 x 2 = 53
8 x 4 + 5 x 3 + 2 x 2 = 51
10 x 2 + 1 x 3 + 4 x 4 = 39
9 x 3 + 1 x 2 + 5 x 4 = 49
Therefore, there may be 1 or 3 tricycles in the parking lot.