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3 years ago

Several polynomial functions are graphed. Which graph displays a polynomial function with all even exponents?

Mathematics

2 answers:

grandymaker [24]3 years ago

7 0

Answer:

Option C

Step-by-step explanation:

Let's look at the graphs one by one:

The graph has rising and falling exponential functions, therefore, it will not fit the pattern. The graph has a negative exponent function.

Let's skip graph C.

Graph B looks like the correct answer, however, the graph has a negative exponent and then rises up again.

Graph D is out of question as it has uneven exponents.

Graph C has an even function.

mihalych1998 [28]3 years ago

4 0

So from the looks of it i would say c ( really sorry if i am wrong)

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A college is currently accepting students that are both in-state and out-of-state. They plan to accept three times as many in-st

densk [106]

Answer:

\[y < = 300\]

Step-by-step explanation:

Let x = number of out-of-state students at the college

Let y = number of in-state students at the college

As per the given problem, the constraints are as follows:

\[x < = 100\] --------- (1)

\[y = 3 * x\] --------- (2)

From the given equations (2), \[ x = y/3 \]

Substituting in (1):

\[y/3 < = 100\]

Or, \[y < = 300\] which is the constraint representing the incoming students.

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3 years ago

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The length of a rectangular floor is 2 feet more than its width. The area of the floor is 168 square feet. Kim wants to use a ru

ioda

Let width of the floor be x feet, them area is
x(x+2) = 168
x^2 + 2x - 168 = 0
(x - 12)(x + 14) - 0
so x = 12
the floor is 12 ft by 10 ft

the width of the rug should be 10 - 2(2) = 6 feet

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3 years ago

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit

Andre45 [30]

2x + 3y = 1470
3y = -2x + 1470
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2 years ago

Need help with math question

mote1985 [20]

Answer:

(-7,4)

Step-by-step explanation:

goal: (y-k)^2=4p(x-h)

y^2-8y=4x+12 Rearranged and added 4x and 12 on both sides

y^2-8y+(-8/2)^2=4x+12+(-8/2)^2 complete square time (add same thing on both sides)

y^2-8y+(-4)^2=4x+12+(-4)^2 (simplify inside the squares)

(y-4)^2=4x+12+16 (now write the left hand side as a square)

(y-4)^2=4x+28

(y-4)^2=4(x+7) factored...

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3 years ago

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Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

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3 years ago