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ivanzaharov [21]
3 years ago
15

Several polynomial functions are graphed. Which graph displays a polynomial function with all even exponents?

Mathematics
2 answers:
grandymaker [24]3 years ago
7 0

Answer:

Option C

Step-by-step explanation:

Let's look at the graphs one by one:

The graph has rising and falling exponential functions, therefore, it will not fit the pattern. The graph has a negative exponent function.

Let's skip graph C.

Graph B looks like the correct answer, however, the graph has a negative exponent and then rises up again.

Graph D is out of question as it has uneven exponents.

Graph C has an even function.

mihalych1998 [28]3 years ago
4 0
So from the looks of it i would say c ( really sorry if i am wrong)
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Answer:

\[y < = 300\]

Step-by-step explanation:

Let x = number of out-of-state students at the college

Let y = number of in-state students at the college

As per the given problem, the constraints are as follows:

\[x < = 100\]    --------- (1)

\[y = 3 * x\]      --------- (2)

From the given equations (2), \[ x = y/3 \]

Substituting in (1):

\[y/3 < = 100\]

Or, \[y < = 300\] which is the constraint representing the incoming students.

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3 years ago
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The length of a rectangular floor is 2 feet more than its width. The area of the floor is 168 square feet. Kim wants to use a ru
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Let width of the floor be x feet, them area is
x(x+2)  = 168
x^2 + 2x - 168 = 0
(x - 12)(x + 14) - 0
so x = 12
the floor is 12 ft by 10 ft

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Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit
Andre45 [30]
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2 years ago
Need help with math question
mote1985 [20]

Answer:

(-7,4)

Step-by-step explanation:

goal: (y-k)^2=4p(x-h)

y^2-8y=4x+12    Rearranged and added 4x and 12 on both sides

y^2-8y+(-8/2)^2=4x+12+(-8/2)^2 complete square time (add same thing on both sides)

y^2-8y+(-4)^2=4x+12+(-4)^2 (simplify inside the squares)

(y-4)^2=4x+12+16  (now write the left hand side as a square)

(y-4)^2=4x+28

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vertex is (-7,4)

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3 years ago
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Because of their connection with secant​ lines, tangents, and instantaneous​ rates, limits of the form ModifyingBelow lim With h
Gre4nikov [31]

Answer:

\dfrac{1}{2\sqrt{x}}

Step-by-step explanation:

f(x) = \sqrt{x} = x^{\frac{1}{2}}

f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}

We use binomial expansion for (x+h)^{\frac{1}{2}}

This can be rewritten as

[x(1+\dfrac{h}{x})]^{\frac{1}{2}}

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(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots

Setting x=\dfrac{h}{x} and n=\frac{1}{2},

(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots

=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots

Multiplying by x^{\frac{1}{2}},

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

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The limit of this as h\to 0 is

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