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anyanavicka [17]
3 years ago
5

in parallelogram ABCD, diagonals AC and BD intersect at E. Which statement proves ABCD is a rectangle?

Mathematics
1 answer:
Fofino [41]3 years ago
5 0

Answer:

AC ≅ BD

Step-by-step explanation:

A parallelogram is a shape that have two pairs of parallel sides with opposite sides having the same length and opposite angles having the same size.

A rectangle is a shape that have two pairs of parallel sides with opposite sides having the same length and each of the four angles is 90°.

A parallelogram is said to be a rectangle if the diagonals of the parallelogram are of the same size (congruent). Therefore in parallelogram ABCD, ABCD is a rectangle if AC is equal to BD. where AC and BD are the diagonals

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