Answer: Order will be F,D,C and Fourth Option is correct and x = 10
Step-by-step explanation:
Since we have given that
![\sqrt{6x+4}=8](https://tex.z-dn.net/?f=%5Csqrt%7B6x%2B4%7D%3D8)
We first transpose the square root to the right , so it becomes square of 8,i.e.
![6x+4=8^2\\\\6x+4=64](https://tex.z-dn.net/?f=6x%2B4%3D8%5E2%5C%5C%5C%5C6x%2B4%3D64)
Now, transpose 4 to the right so it will get subtract from 64 i.e.
![6x=64-4\\\\6x=60](https://tex.z-dn.net/?f=6x%3D64-4%5C%5C%5C%5C6x%3D60)
Since 6 is multiplied to x on tranposing it will get divided by 60 i.e.
![x=\frac{60}{6}\\\\x=10](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B60%7D%7B6%7D%5C%5C%5C%5Cx%3D10)
Hence, on simplification, we get x=10.
Hence , the order is F,D,C.