Answer: 1/6
Step-by-step explanation: Let the no of females be x
The no of males be 5x
The total no of males and females in the math course be 5x+x= 6x
The fraction of females is x/6x = 1/6
Answer:
a. The value of the constant k is 21
b. The equation is y = k * x, where k is the proportionality constant, "x" is the number of terraced houses and "y" is the width of a row of identical houses.
Step-by-step explanation:
a.
<em>A proportional relationship satisfies the equation y = k * x, where k is a positive constant and is called a proportionality constant. In this case "x" is the number of terraced houses and "y" is the width of a row of identical houses.
</em>
The data you have is that the width of 5 townhouses are 105 feet. This means that the value of "x" is 5 houses and the value of "y" is 105 feet. By replacing in the equation y = k * x and isolating the constant k, you get:
<em>105=k*5
</em>

<em>k=21
</em>
<u><em>So the value of the constant k is 21.</em></u>
b.
<em>As mentioned, the equation is y = k * x, where k is the proportionality constant, "x" is the number of terraced houses and "y" is the width of a row of identical houses.</em>
This means that just as "x" increases, "y" increases. And that if "x" decreases, "y" will decrease. And this relationship between "x" e "and" will always be the same, determined by the value of the constant "k".
43 and 5/6 because 12 and 1/4*2 is 24 and 1/2 then 9 and 2/3*2 is 19 and 1/3 and when you add that you get 43 and 5/6
Step-by-step explanation:
so x+y=2
a line would have to go 0,2 2,0
so the answer would be D
Answer:
4. H0: u1= u2 Ha; u1≠ u2
5. The smaller value of p supports the null hypothesis.
Step-by-step explanation:
4. The null and alternate hypotheses are
H0: u1= u2 i.e there no difference between the mean pinch strengthof the two surgeries
against the claim
Ha; u1≠ u2 i.e there a difference between the mean pinch strengthof the two surgeries
It can be written like this as well
H0: u1 -u2= 0 i.e there no difference between the mean pinch strengthof the two surgeries
against the claim
Ha; u1 -u2≠ 0 i.e there a difference between the mean pinch strengthof the two surgeries
Part 5. The test having a p- value less than 0.05 tells that the null hypothesis cannot be rejected. Theres no evidence to reject the null hypothesis.
The smaller value of p supports the null hypothesis.