Answer:
Step-by-step explanation:
Hello There!
For this problem we want to split the irregular 3d figure into two regular 3d figures
Two rectangular prisms with the following dimensions
rectangular prism 1
length - 5 feet
width - 12 feet
height - 5 feet
rectangular prism 2
length - 5 feet
width - 5 feet
height - 10 feet (was found by subtract height of rectangular prism 1 (5 feet) from the total height of the irregular figure (15-5=10 so the height of rectangular prism 2 is 10 feet)
Now to find the volume of each individual prism...
So remember the formula for volume of a rectangular prism is
volume = length x width x height
so having the dimensions of each rectangular prism we plug in each value to the formula ( remember we're doing this for each individual rectangular prism)
For rectangular prism 1
V = 12 x 5 x 5
12x5x5=300 so the volume of rectangular prism is 300 cubic feet
For rectangular prism 2
V = 10 x 5 x 5
10x5x5=250 so the volume of rectangular prism is 250 cubic feet
our final step is to add the two volumes together
250 + 300 = 550
so we can conclude that the volume of the rooftop is 550
Hello from MrBillDoesMath!
Answer:
Area of tile = 24
Discussion:
The area of the triangle is
(1/2) Base * height =
(1/2) 6 * 8 =
(1/2) 48 =
24
Thank you,
MrB
Answer:
okay so its 25% C
25%= $12
100%= free
75= $4 12 dollars off
50= $8
every 25% is 4 dollars so
25= $4 off
50= $8 off
75= $12 off
100%= $16 off
Step-by-step explanation:
Answer:
Yes, there is sufficient evidence to conclude that performance on the problem solving task is lowered by having onlookers.
Step-by-step explanation:
Null hypothesis: The performance on the problem solving task is lowered by having onlookers.
Alternate hypothesis: The performance on the problem solving task is not lowered by having onlookers.
Test statistic (t) = (sample mean - population mean) ÷ (sample sd/√n)
sample mean = 89.8
population mean = 89.1
sample sd = √sample variance = √84.6 = 9.198
n = 21
Degree of freedom = n-1 = 21-1 = 20
Assuming a 5% significance level
The test is a two-tailed test. Critical values corresponding to 20 degrees of freedom and 5% significance level are -2.086 and 2.086
Test statistic (t) = (89.8 - 89.1) ÷ (9.198/√21) = 0.7 ÷ 2.007 = 0.349
Conclusion:
Fail to reject the null hypothesis because the test statistic 0.349 falls within the region bounded by the critical values.
There is sufficient evidence to conclude that performance on the problem solving task is lowered by having onlookers.
