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kiruha [24]
3 years ago
8

How old are you if you graduated college in 2008?

Mathematics
2 answers:
OverLord2011 [107]3 years ago
3 0
25 roughly. Or 24 .....
liraira [26]3 years ago
3 0

Answer:

25-27

Step-by-step explanation:

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Pls answer asap 7 - 3 r = r - 4 ( 2 + r)​
Marianna [84]

Answer:

no real answer

Step-by-step explanation:

distribute the -4 and combine all of the like terms on the left side = r-8-4r, then -8-3r

then we have 7-3r=-8-3r

from here, we can already tell that there's no real answer. this is because the two -3r will cancel, leaving no variable.

since 7 doesn't equal -8, there is no answer.

if, for example, the value on both sides of the equal sign were the same after the variable was eliminated, then your answer would be all real numbers

8 0
2 years ago
In the diagram, DC is tangent to the circle, AC = 12 cm, and BD=2134 cm. Find AD.
olasank [31]
The answer is D Because in a tangent
4 0
3 years ago
Is the number 5 prime, composite, or neither?
OlgaM077 [116]

Answer:

A number that is divisible only by itself and 1 

therefore 5 is a prime number

3 0
3 years ago
Read 2 more answers
Suppose you have 5 riders and 5 horses, and you want to pair them off so that every rider is assigned one horse (and no horse is
maw [93]

There are 120 ways in which 5  riders and 5 horses can be arranged.

We have,

5 riders and 5 horses,

Now,

We know that,

Now,

Using the arrangement formula of Permutation,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

So,

For n = 5,

And,

r = 5

As we have,

n = r,

So,

Now,

Using the above-mentioned formula of arrangement,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

Now,

Substituting values,

We get,

^5N_5 = \frac{5!}{(5-5)!}

We get,

The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,

So,

There are 120 ways to arrange horses for riders.

Hence we can say that there are 120 ways in which 5  riders and 5 horses can be arranged.

Learn more about arrangements here

brainly.com/question/15032503

#SPJ4

7 0
2 years ago
Elliot had 638 fewer marbles than Ravi had. Ravi then gave 352 marbles to Elliot. Who had more marbles in the end. How many more
irga5000 [103]
Elliot because it said that he had 638 fewer than him the Ravi gave him 352 so that would make Elliot have more
5 0
3 years ago
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