4/3 of the area of the larger hexagon to the area of the smaller hexagon
Let the sides of the interior hexagon be 2 cm long, then this hexagon is made up of 6 equilateral triangles of side = 2.
The area of this hexagon = 6 * 1 * sqrt3 = 6 sqrt3 ( as the triangle is made up of 2 60-30-90 triangles)
The exterior hexagon is made up of 6 equilateral triangles with altitude 2 and the area = 6 * 2 * (2 / sqrt3 ) = 24 / sqrt3
area exterior hex / interior hex = 24 / sqrt3 * 1 / 6sqrt3 = 24/18
= 4/3
Required ratio = 4/3 answer
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The answer would be around 4.5 or 4.6
Answer:
You can just write Quadrant I: All values are positive, Quadrant II: Sine is positive, Quadrant III: Tangent is positive, and Quadrant IV: Cosine is positive.
Answer:
F=0.46N
Step-by-step explanation:
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