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3 years ago

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Mathematics

1 answer:

Butoxors [25]3 years ago

5 0

Answer:

g=3

Step-by-step explanation:

f(g) = g^2 +3g

Let f(g) = 18

18 = g^2 +3g

Subtract 18 from each side

18-18 =g^2 +3g-18

0 = g^2 +3g-18

Factor

0 = (g+6) (g-3)

Using the zero product property

g+6 =0 g-3 =0

g = -6 g =3

The only solution listed is g=3

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Records for the past several years show that 46% of customers at a local game shop use a customer loyalty card. Due to a recent

Ratling [72]

Answer:

1. Null hypotheses: p=0.49

Alternative hypotheses: p>0.49

2. p=0.5704 or 57.04%

Step-by-step explanation:

We have to writer the hypotheses for testing the proportion has increased from 49%. So, the population proportion that is to be tested is 0.49.

As we already know that the null hypotheses always contain equality so,

Null hypotheses: p=0.49

and we have to test whether the proportion has increased from 0.49, so,

Alternative hypotheses: p>0.49

Thus, the hypotheses for testing the proportion has increased from 49% are

Null hypotheses: p=0.49

Alternative hypotheses: p>0.49

We have to find the proportion of sampled customers using loyalty card.

The given sample indicate that 77 out of 135 customers are using loyalty card. So,

p=x/n

where x is the number of favorable outcome and n is total number of outcome.

Here, x=77 and n=135. So,

p=77/135=0.5704 or 57.04%

6 0

3 years ago

If f(x)=x^2-11x+18 what are the zeros of the function?

UkoKoshka [18]

X= 9 x=2
-2 × -9=18
-2 + -9= -11

8 0

3 years ago

Which expression is equivalent to 5^3?

AleksAgata [21]

Answer:

C and D

Step-by-step explanation:

5^3 - 5^0 = 125 - 1 = 124, so it's not A

5^12 / 5^4 = 5^(12-4) = 5^8, so it's not B

5^7 * 5^-4 = 5^(7+(-4)) = 5^3, so it can be C

5^0 * 5^3 = 5^(0+3) = 5^3, so it can be D

5 + 5^2 = 5 + 25 = 30, so it can't be E

3 0

3 years ago

Givien h(x) = -x- 5, find h(-6)

garik1379 [7]

Answer:

h(-6) = 1

Step-by-step explanation:

Hello!

Substitute -6 for x in the equation.

<h3>Evaluate</h3>

h(x) = -x - 5
h(-6) = -(-6) - 5
h(-6) = 6 - 5
h(-6) = 1

h(-6) is 1.

3 0

2 years ago

A Simple random sample of 100 8th graders at a large suburban middle school indicated that 84% of them are involved with some ty

Setler [38]

Answer: a) (0.755, 0.925)

Step-by-step explanation:

Let p be the population proportion of 8th graders are involved with some type of after school activity.

As per given , we have

n= 100

sample proportion: $\hat{p}=0.84$

Significance level : $\alpha= 1-0.98=0.02$

Critical z-value : $z_{\alpha/2}=2.33$ (using z-value table)

Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

i.e. $0.84\pm (2.33)\sqrt{\dfrac{0.84(1-0.84)}{100}}$

i.e. $\approx0.84\pm 0.085$

i.e. $(0.84- 0.085,\ 0.84+ 0.085)=(0.755,\ 0.925)$

Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)

3 0

4 years ago

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