All categories

3 years ago

Do all regular polygons have point symmetry? Explain.

Mathematics

2 answers:

Goshia [24]3 years ago

8 0

Answer:

Nope.

Hey mate, here is your answer. Hope it helps you.

Step-by-step explanation:

No,not all polygons have symmetry. Only regular polygons who have same number of sides have point symmetry. Point Symmetry is when every part has a matching part the same distance from the central point but in the opposite direction.

lubasha [3.4K]3 years ago

4 0

The answer is D) No, because all regular polygons do not have rotational symmetry of 180° on Edge 2020

You might be interested in

What is the number written in standard notation?

expeople1 [14]

Answer:

option B

Step-by-step explanation:

To find the number which is written in the standard form, $5 \times {10}^{3}$

We expand ${10}^{3}$ and multiply by 5 to get

$= 5 \times (10 \times 10 \times 10)$

$=5\times 1000$

=5000

5 0

3 years ago

Read 2 more answers

Would 45% of 160 be greater than or less than 80?

Nadusha1986 [10]

45% is less than 80. The actual answer is 72. Hope that helps :)

4 0

3 years ago

A building in the shape of a pyramid was recently built. Each side of the pyramid’s square base has a length of 40 feet and the

Alex

Answer:32,000ft^3

Step-by-step explanation:

3 0

3 years ago

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

A bag has 4 green marbles, 3 red marbles, and 3 yellow marbles. What is the probability that you pick

STALIN [3.7K]

$|\Omega|=10\cdot9=90\\ |A|=3\cdot3=9\\\\ P(A)=\dfrac{9}{90}=\dfrac{1}{10}=10\%$

6 0

3 years ago

Read 2 more answers