Answer:
The dimensions of the yard are W=20ft and L=40ft.
Step-by-step explanation:
Let be:
W: width of the yard.
L:length.
Now, we can write the equation of that relates length and width:
(Equation #1)
The area of the yard can be expressed as (using equation #1 into #2):
(Equation #2)
Since the Area of the yard is
, then equation #2 turns into:

Now, we rearrange this equation:

We can divide the equation by 5 :

We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since
and
. The equation factorised looks like this:

Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:

Therefore, the dimensions of the yard are W=20ft and L=40ft.
Anything more or less than 1 would result in a different outcome, and anything times 1 results in itself.
Given:
AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.
To find:
The
and
.
Solution:
AD is diameter of the circle. So, the measure of arc AD is 180 degrees.




The measure inscribed angle is half of the corresponding subtended arc.



AB is the tangent. So,
because radius is perpendicular on the tangent and the point of tangency.




Therefore,
and
.
Answer:
0.16
Step-by-step explanation:
Given the data:
Students __ `Gr_9 __Gr_10 __ G_11 __G_12
Frequency : 152 ___130 ______ 80 ___98
The probability is :
Frequency of grade 11 / number of trials
80 / 500