All categories

3 years ago

What is the midpoint

Mathematics

1 answer:

liq [111]3 years ago

5 0

Answer:

midpoint formula:

x1+x2/2 y1+y2/2

-4 + (-2)/2 which then simplifies to -6/2 and then to -3

2 + 2 /2 which then simplifies to 2

x= -3

y= 2

so (-3,2) is the coordinate point of the midpoint of this segment

You might be interested in

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago

Tell whether the triangle is a right triangle. Show Work.

Yakvenalex [24]

Answer:

This is not a right triangle because the hypotenuse is less than the two sides and aren't equal when following the Pythagorean thm

Step-by-step explanation:

To confirm if a triangle is a right triangle, we must use the Pythagorean thm

a^2 + b^2 = c^2

23^2 + 11.4^2 = 21.2^2

529 + 129.96 = 449.44

658.96 ≠ 449.44

7 0

3 years ago

3. Please help me with this question

bagirrra123 [75]

Answer:

Step-by-step explanation:

Multiply the exponents together

6 0

3 years ago

I Only Need #9 Not 10

Minchanka [31]

Answer:

Step-by-step explanation:

Remember the last question? to find circumference you have to multiply the diameter by 3.14? well same here except you divide the circumference by 3.14 to get the diameter. so divide 18.84 ÷ 3.14 = 6

~R3V0

$d= \frac{C}{\pi }$