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MAXImum [283]
3 years ago
14

what value in place of the question mark makes the polynomial below a perfect square trinomial 9x^2+?x+49

Mathematics
2 answers:
puteri [66]3 years ago
8 0

Answer:

The required value is 42 which makes the polynomial a perfect square trinomial.    

Step-by-step explanation:

Given the trinomial

9x^2+?x+49

we have to find the value in the place of question mark which makes the polynomial above a perfect square trinomial.

By the identity of perfect square

a^2+2ab+b^2=(a+b)^2

\text{Here given the polynomial with above identity }9x^2+?x+49

(3x)^2+?x+7^2

which given a=3x, b=7

Hence, put these values in identity we get

(3x)^2+2(3x)7+7^2=(3x+7)^2

9x^2+42x+49=(3x+7)^2

Hence, the required value is 42 which makes the polynomial a perfect square trinomial.

Tatiana [17]3 years ago
5 0
Hello : 
9x²+ bx +49 = (3x)² +2(3x)(7) +7²
so : b = 42
9x²+42x+49 = ( 3x+7)²....( <span>perfect square trinomial)</span>
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