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3 years ago

6

Dave delivered 52 newspapers all together on Saturday and Sunday. He delivered 8 more newspapers on Sunday than on Saturday. How

many newspapers did Dave deliver on Sunday?
Please show work.

1 answer:

Harman [31]3 years ago

4 0

Let x=papers on Saturday and y=papers on Sunday

First make equations for the information given to you

x+y=52 (total papers) and y= x+8 (he sold 8 more on Sunday)

then since you know y=x+8 then substitute it in the other equation like so

x+(x+8)=52 which means 2x+8=52 which means 2x=44 and therefore x=22

the problem however asks for sunday and not saturday, so solve for y now

y=x+8 which means y=22+8 which means y=30

He sold 30 papers on Sunday

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A Halloween trick-or-treat group consists of 3 Trolls, 4 Nazguls, 4 Ents, and 5 Pokemon. A committee of 4 is to be picked to rep

balu736 [363]

Answer:

The probability that the committee will consist of 1 from each type of monster is 0.1318 and Suppose that the Pokemon refuse to be on the same committee as a the Trolls.So,the probability that this type of committee is formed is 0.5357

Step-by-step explanation:

No. of Trolls = 3

No. of Nazguls =4

No. of Ents = 4

No. of Pokemon = 5

Total Monsters = 16

We are given that A committee of 4 is to be picked to represent the group at the Monster Bash.

(a) Find the probability that the committee will consist of 1 from each type of monster.

So, the probability that the committee will consist of 1 from each type of monster:

= $\frac{^3C_1 \times ^4C_1 \times ^4C_1 \times ^5C_1}{^{16}C_4}$

= $\frac{\frac{3!}{1!(3-1)!} \times \frac{4!}{1!(4-1)!} \times \frac{4!}{1!(4-1)!}\times \frac{5!}{1!(5-1)!}}{\frac{16!}{4!(16-4)!}}$

= $\frac{\frac{3!}{1!(2)!} \times \frac{4!}{1!(3)!} \times \frac{4!}{1!(3)!}\times \frac{5!}{1!(4)!}}{\frac{16!}{4!(12)!}}$

= $0.1318$

b)Suppose that the Pokemon refuse to be on the same committee as a the Trolls.

So, the probability that this type of committee is formed

= $\frac{(^3C_3 \times ^8C_1)+(^3C_2 \times ^8C_2)+(^3C_1 \times ^8C_3)+(^3C_0 \times ^8C_4)+(^5C_4 \times ^8C_0)+(^5C_3 \times ^8C_1)+(^5C_2 \times ^8C_2)+(^5C_1 \times ^8C_3)}{^{16}C_4}$

= $\frac{(\frac{3!}{3!(3-3)!} \times \frac{8!}{1!(8-1)!})+(\frac{3!}{2!(3-2)!} \times\frac{8!}{2!(8-2)!})+(\frac{3!}{1!(3-1)!} \times\frac{8!}{3!(8-3)!})+(\frac{3!}{0!(3-0)!} \times \frac{8!}{4!(8-4)!})+(\frac{5!}{4!(5-4)!} \times \frac{8!}{0!(8-0)!})+(\frac{5!}{3!(5-3)!} \times \frac{8!}{1!(8-1)!})+(\frac{5!}{2!(5-2)!} \times\frac{8!}{2!(8-2)!})+(\frac{5!}{1!(5-1)!} \times \frac{8!}{3!(8-3)!})}{\frac{16!}{4!(16-4)!}}$

= $0.5357$

Hence The probability that the committee will consist of 1 from each type of monster is 0.1318 and Suppose that the Pokemon refuse to be on the same committee as a the Trolls.So,the probability that this type of committee is formed is 0.5357

4 0

3 years ago

Mr. Wilson has $3,000 in his bank account. Ms. Nelson has 10 times as much money in her bank account as Mr. Wilson has in his ba

laiz [17]

Since Mr. Wilson has $3,000 and Ms. Nelson has 10 times more than that, we can set up a basic equation determining how much money Ms. Nelson has.

$(10)(3000)=30000$

Ms. Nelson has $30,000 while Mr. Wilson has only $3,000.

8 0

3 years ago

Read 2 more answers

Which figure has 2 pairs of parallel sides 2 pairs of sides of equal length and 4 right angle

elixir [45]

The figure is a parallelogram.

3 0

4 years ago

HELPPPPPPPPP i have the most trouble with math what’s the answer??

densk [106]

For this case we must simplify the following expression:

$\frac {\sqrt {120}} {\sqrt {30}}$

We know that: $120 = 30 * 4 = 30 * 2 ^ 2$

By definition of power properties we have to:

$\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}$

Rewriting the given expression we have:

$\frac {\sqrt {2 ^ 2 * 30}} {\sqrt {30}} =\\\frac {2 \sqrt {30}} {\sqrt {30}} = 2$

Answer:

Option A

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3 years ago

4 1/3 - 1 2/3 how to solve this please

8_murik_8 [283]

Answer:

$2\frac{2}{3}$

Step-by-step explanation:

1) Convert $4\frac{1}{3}$ to improper fraction. Use this rule: $a\frac{b}{c} =\frac{ac+b}{c}$ .

$\frac{4\times3+1}{3} -1\frac{2}{3}$

2) Simplify 4 * 3 to 12.

$\frac{12+1}{3}$

3) Simplify 12 + 1 to 13.

$\frac{13}{3} -1\frac{2}{3}$

4) Convert $1\frac{2}{3}$ to improper fraction. Use this rule: $a\frac{b}{c} =\frac{ac+b}{c}$ .

$\frac{13}{3} -\frac{1\times3+2}{3}$

5) Simplify 1 * 3 to 3.

$\frac{13}{3} -\frac{3+2}{3}$

6) Simplify 3 + 2 to 5.

$\frac{13}{3} -\frac{5}{3}$

7) Join the denominators.

$\frac{13-5}{3}$

8) Simplify.

$\frac{8}{3}$

9) Convert to mixed fraction.

$2\frac{2}{3}$

(Decimal Form: 2.666667)

Thank you,
Eddie

3 0

2 years ago