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3 years ago

8

What is the value of x in 5x−3(x−11)=7(2x−5)+2

1 answer:

riadik2000 [5.3K]3 years ago

4 0

The value of x is 5.5. I got this answer by first distributing -3 amongst (x-11), and distributing 7 amongst (2x-5). Next I combined like terms and subtracted 3x from 5x, and added -35 and 2. Next I subtracted 33 from both sides. Next I subtracted 14x from both sides. And finally I divided both sides by -12 to get the final answer of 5.5.

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Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =

Rainbow [258]

Answer:

$\sin L = 0.60$

$tan\ N = 1.33$

$\cos L = 0.80$

$\sin N = 0.80$

Step-by-step explanation:

Given

See attachment

From the attachment, we have:

$MN = 6$

$LN = 10$

First, we need to calculate length LM,

Using Pythagoras theorem:

$LN^2 = MN^2 + LM^2$

$10^2 = 6^2 + LM^2$

$100 = 36 + LM^2$

Collect Like Terms

$LM^2 = 100 - 36$

$LM^2 = 64$

$LM = 8$

Solving (a): $\sin L$

$\sin L = \frac{Opposite}{Hypotenuse}$

$\sin L = \frac{MN}{LN}$

Substitute values for MN and LN

$\sin L = \frac{6}{10}$

$\sin L = 0.60$

Solving (b): $tan\ N$

$tan\ N = \frac{Opposite}{Adjacent}$

$tan\ N = \frac{LM}{MN}$

Substitute values for LM and MN

$tan\ N = \frac{8}{6}$

$tan\ N = 1.33$

Solving (c): $\cos L$

$\cos L = \frac{Adjacent}{Hypotenuse}$

$\cos L = \frac{LM}{LN}$

Substitute values for LN and LM

$\cos L = \frac{8}{10}$

$\cos L = 0.80$

Solving (d): $\sin N$

$\sin N = \frac{Opposite}{Hypotenuse}$

$\sin N = \frac{LM}{LN}$

Substitute values for LM and LN

$\sin N = \frac{8}{10}$

$\sin N = 0.80$

7 0

3 years ago

How do you solve <br> 69-3a=0

aleksandrvk [35]

69 - 3a = 0

69 - 3a (-69) = 0 (-69)

-3a = -69

-3a(/-3) = -69(/-3)

a = 23

hope this helps

8 0

3 years ago

Formula for the volume of a square pyramid, v=1/3lwh for w

tatuchka [14]

$\dfrac{1}{3}lwh=V\qquad|\text{multiply both sides by 3}\\\\lwh=3V\qquad|\text{divide both sides by}\ lh\neq0\\\\\boxed{w=\dfrac{3V}{lh}}$

3 0

3 years ago

Perform the following operations and prove closure. Show your work.<br><br> (x/x+3) + (x+2/x+5)

Westkost [7]

Answer:

$\frac{2(x^{2} + 5x + 3)}{(x+3)(x+5)}$

Step-by-step explanation:

We need to sum the following two expressions:

$\frac{x}{x+3} + \frac{x+2}{x+5}$

$\frac{x(x+5) + (x+2)(x+3)}{(x+3)(x+5)}$

expanding the polynomial in the numerator:

$\frac{2x^{2} + 10x + 6}{(x+3)(x+5)}$

$\frac{2(x^{2} + 5x + 3)}{(x+3)(x+5)}$

This is the most simplified form we can get:

$\frac{2(x^{2} + 5x + 3)}{(x+3)(x+5)}$

8 0

3 years ago

Read 2 more answers

I WILL AWARD BRAINLIEST!

gavmur [86]

Answer:

A. 70

Step-by-step explanation:

You can use the transversals and use vertical angles are congruent.

7 0

3 years ago

Read 2 more answers