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Greeley [361]
3 years ago
8

What is the value of x in 5x−3(x−11)=7(2x−5)+2

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
4 0
The value of x is 5.5. I got this answer by first distributing -3 amongst (x-11), and distributing 7 amongst (2x-5). Next I combined like terms and subtracted 3x from 5x, and added -35 and 2. Next I subtracted 33 from both sides. Next I subtracted 14x from both sides. And finally I divided both sides by -12 to get the final answer of 5.5.
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Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =
Rainbow [258]

Answer:

\sin L = 0.60

tan\ N = 1.33

\cos L = 0.80

\sin N = 0.80

Step-by-step explanation:

Given

See attachment

From the attachment, we have:

MN = 6

LN = 10

First, we need to calculate length LM,

Using Pythagoras theorem:

LN^2 = MN^2 + LM^2

10^2 = 6^2 + LM^2

100 = 36 + LM^2

Collect Like Terms

LM^2 = 100 - 36

LM^2 = 64

LM = 8

Solving (a): \sin L

\sin L = \frac{Opposite}{Hypotenuse}

\sin L = \frac{MN}{LN}

Substitute values for MN and LN

\sin L = \frac{6}{10}

\sin L = 0.60

Solving (b): tan\ N

tan\ N = \frac{Opposite}{Adjacent}

tan\ N = \frac{LM}{MN}

Substitute values for LM and MN

tan\ N = \frac{8}{6}

tan\ N = 1.33

Solving (c): \cos L

\cos L = \frac{Adjacent}{Hypotenuse}

\cos L = \frac{LM}{LN}

Substitute values for LN and LM

\cos L = \frac{8}{10}

\cos L = 0.80

Solving (d): \sin N

\sin N = \frac{Opposite}{Hypotenuse}

\sin N = \frac{LM}{LN}

Substitute values for LM and LN

\sin N = \frac{8}{10}

\sin N = 0.80

7 0
3 years ago
How do you solve <br> 69-3a=0
aleksandrvk [35]
69 - 3a = 0

69 - 3a (-69) = 0 (-69)

-3a = -69

-3a(/-3) = -69(/-3)

a = 23

hope this helps
8 0
3 years ago
Formula for the volume of a square pyramid, v=1/3lwh for w
tatuchka [14]

\dfrac{1}{3}lwh=V\qquad|\text{multiply both sides by 3}\\\\lwh=3V\qquad|\text{divide both sides by}\ lh\neq0\\\\\boxed{w=\dfrac{3V}{lh}}

3 0
3 years ago
Perform the following operations and prove closure. Show your work.<br><br> (x/x+3) + (x+2/x+5)
Westkost [7]

Answer:

\frac{2(x^{2} + 5x + 3)}{(x+3)(x+5)}

Step-by-step explanation:

We need to sum the following two expressions:

\frac{x}{x+3} + \frac{x+2}{x+5}

\frac{x(x+5) + (x+2)(x+3)}{(x+3)(x+5)}

expanding the polynomial in the numerator:

\frac{2x^{2} + 10x + 6}{(x+3)(x+5)}

\frac{2(x^{2} + 5x + 3)}{(x+3)(x+5)}

This is the most simplified form we can get:

\frac{2(x^{2} + 5x + 3)}{(x+3)(x+5)}

8 0
3 years ago
Read 2 more answers
I WILL AWARD BRAINLIEST!
gavmur [86]

Answer:

A. 70

Step-by-step explanation:

You can use the transversals and use vertical angles are congruent.

7 0
3 years ago
Read 2 more answers
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