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marishachu [46]
2 years ago
9

A bag of marbles has 3 red, 4 blue, and 5 white marbles in it. What is the probability of reaching in and selecting a blue marbl

e? (without looking)
Mathematics
1 answer:
goblinko [34]2 years ago
4 0

Answer:

P(B)=\frac{1}{3}

Step-by-step explanation:

The number of red marbles in the bag is; n(R)=3.

The number of blue marbles in the bag is; n(B)=4.

The number of white marbles in the bag is; n(W)=5.

The total number of marbles in the bag is: n(S)=3+4+5=12.

The probability of selecting a blue marble is P(B)=\frac{n(B)}{n(S)}

We substitute the given information to obtain:

P(B)=\frac{4}{12}

We simplify to obtain:

P(B)=\frac{1}{3}

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Answer:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

Step-by-step explanation:

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Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a

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y=ax^2 -2ax+c

The y-coordinate of the vertex:

y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10

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1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1

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Parabola equation:

y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}

2nd boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0

Equation:

y=ax^2+c

The y-coordinate of the vertex:

y_v=a\cdot 0^2+c\Rightarrow c=-7

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1=a\cdot (-8)^2-7\\ \\64a-7=1

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Parabola equation:

y=\dfrac{1}{8}x^2 -7

System of two equations:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

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3. subtract that answer from 374,000

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