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Novay_Z [31]
3 years ago
7

Please solve 108 = 2X-4(2X-9)

Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0
108=2x-4(2x-9)
108=2x-8x+36
108=-6x+36
-36         -36
72=-6x
72/-6=-6x/-6
-12=x
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If two lines in a plane intersect then they are not parallel true or false
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3 years ago
Write and solve a system of equations. Be sure to label the variables. The sum of two numbers is twelve. Two times the first num
adoni [48]

The solution to the system of equations is x = 8, y = 4.

<h3>How to write the system of equations?</h3>

First, let's define our variables as x and y.

"the sum of two numbers is twelve" is written as:

x + y = 12

"two times the first number minus three times the second number is four" is written as:

2x - 3y = 4

Then the system of equations is:

x + y  = 12

2x - 3y = 4

<h3>How to solve it?</h3>

First, we isolate one of the variables in one equation, I will isolate x on the first one to get:

x = 12 - y

Now we replace this on the other equation, so we get:

2*(12 - y) - 3y = 4

Now we can solve this for y.

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Now we know the value of y, and:

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If you want to learn more about systems of equations, you can read:

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7 0
2 years ago
What is the product of 2x + y and 5x – y + 3?
hoa [83]

Answer:  The required product is 10x^2-y^2+3xy+6x+3y.

Step-by-step explanation:  We are to find the product f the following two algebraic expressions:

E_1=2x+y,\\\\E_2=5x-y+3.

To find the product of the above two expressions, we must multiply each term of the first expression with each term of the second expression.

The multiplication is as follows:

M\\\\=E_1 \times E_2\\\\=(2x+y)\times(5x-y+3)\\\\=10x^2-2xy+6x+5xy-y^2+3y\\\\=10x^2-y^2+3xy+6x+3y.

Thus, the required product is 10x^2-y^2+3xy+6x+3y.

7 0
3 years ago
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