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kodGreya [7K]
3 years ago
6

How to find the area of the shaded region?

Mathematics
1 answer:
MaRussiya [10]3 years ago
5 0
Depends on the shape of the region. Need more information.
You might be interested in
Midpoint (10,4) Endpoint (9,-4), find the coordinates of the other endpoint.​
mestny [16]

Answer:

(11, 12)

Step-by-step explanation:

<u>Mid point coordinates:</u>

  • x = (x₁ + x₂)/2
  • y = (y₁ + y₂)/2

<u>Since midpoint and one endpoint given (10, 4) and (9, -4), the other endpoint:</u>

  • x₂ = 2x - x₁ = 2*10 - 9 = 11
  • y₂ = 2y - y₁ = 2*4 - (-4) = 12

<u>So the other endpoint is: </u>(11, 12)

4 0
3 years ago
The cost of 5 hats and 1 scarf is $47. The cost of 2 hats and 2 scarves is $40. How much does one hat cost?
stepan [7]

Answer:

6.75

Step-by-step explanation:

h=hat, s=scarf

5h + 1s = $47 (equation 1)

2h + 2s = $40 (equation 2)

multiply equation 1 by 2 , we get: 10h + 2s = $94 (equation 3)

equation 3 minus equation 2, we get:

8h = $54 ⇒ h = $6.75 ⇔ 1 hat cost $6.75

substitute h = $6.75 into equation 2 to find s,

2($6.75) + 2s = $40

$13.5 + 2s = $40

2s = $26.5

s = $13.25 ⇔ 1 scarf cost $13.25

6 0
2 years ago
Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
Pls help asap! It’s due in one hour!!
AfilCa [17]
1. t = 7
2. t = 0
i think? although I’m not 100% sure
8 0
2 years ago
The table below shows the preferences of high school and college students:
Bas_tet [7]
B. looks like the way to go.

5 0
3 years ago
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