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Andru [333]
3 years ago
14

Given cos B = 11/18 find angle B in degrees. Round your answer to the nearest hundredth.

Mathematics
2 answers:
Anastaziya [24]3 years ago
5 0
B = cos^{-1}(\frac{11}{18}) \approx 52.33^\circ
Elden [556K]3 years ago
3 0

Answer:

B\approx 52.33^{\circ}

Step-by-step explanation:

We have been given that \text{cos}(B)=\frac{11}{18}. We are asked to find the measure of angle B.

We will use inverse cosine or arccos to solve for the measure of angle B as:

B=\text{cos}^{-1}(\frac{11}{18})

B=52.33011303567^{\circ}

Upon rounding our answer to nearest hundredth, we will get:

B\approx 52.33^{\circ}

Therefore, the measure of angle B is 52.33 degrees.

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D. The product of a constant factor 5 and a 2-term factor x+2

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1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,
crimeas [40]

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Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222

3 0
4 years ago
Please Help on Math question...
Eddi Din [679]

Answer:

Yes

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Because 9, 12, and 15 are Pythagorean triples

7 0
3 years ago
You order fourteen burritos to go from a Mexican restaurant, six with hot peppers and eight without. However, the restaurant for
Genrish500 [490]

Answer:

0.578

Step-by-step explanation:

If you pick three burritos at random, find the probability of the given event. (Round your answer to three decimal places.)

Given that there are 14 orders at the ratio by of:

6 with hot peppers

8 without hot peppers

At most two have hot peppers.

Binomial Problem with n = 3 ; p(hot) = 6/8

P(0<= x <=2) = 1 - P(x = 3)

= 1 - (6/8)^3

= 1 - ( 3/4 )^3

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= 1- (37/64)

= 1 - 0.421875

= 0.578125

= 0.578

6 0
3 years ago
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