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LekaFEV [45]
2 years ago
10

Identify the composition that is represented by: r (90, 0) T(−2,4)

Mathematics
2 answers:
castortr0y [4]2 years ago
7 0

Answer: left 2

Step-by-step explanation:

Pepsi [2]2 years ago
3 0

The composition of the transformation is (b) A rotation of 90° and then a translation left 2, up 4.

<h3>How to determine the transformation?</h3>

The transformation rule is given as:

r (90, 0) T(−2,4)

The r(90,0) represents a rotation of 90 degrees.

The other part of the transformation rule can be rewritten as:

T(-2,4) => (x - 2,y + 4)

This means a translation right by 2 units and up by 4 units

Hence, the composition of the transformation is (b)

Read more about transformation at:

brainly.com/question/4289712

#SPJ1

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Which sum represents the partial fraction decomposition?​
Alex Ar [27]

It's the last option again. You have 1 linear factor (3<em>x</em>) and 2 copies of a quadratic factor (<em>x</em>² + 10), and the partial fractions with the quadratic factor need to have a linear polynomial in the numerator.

7 0
3 years ago
Help with matrices please? Any wrong/not applicable answers will be reported and BLOCKED
marin [14]

m x H = \left[\begin{array}{ccc}-25&37.5&-12.5\\\9\end{array}\right]

Step-by-step explanation:

Step 1; Multiply 5 with this matrix  \left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right] and we get a matrix \left[\begin{array}{ccc}-5&10\\20&40\\\end{array}\right]

Multiply the fraction  \frac{2}{5} with the matrix  \left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right] and we get \left[\begin{array}{ccc}-\frac{2m}{5} &\frac{4m}{5} \\\frac{8m}{5} &\frac{16m}{5} \\\end{array}\right]

Step2; Now equate corresponding values of the matrices with each other.

-5 = \frac{-2m}{5} and so on. By equating we get the value of m as \frac{25}{2}

Step 3; Add the matrices to get the value of matrix m.

Adding the three matrices on the RHS we get  \left[\begin{array}{ccc}2&9&-9\\\end{array}\right].

Step 4; Adding the matrices on the LHS we get the resulting matrix as H +

\left[\begin{array}{ccc}4&6&-8\\\9\end{array}\right]. Equating the matrices from step 3 and 4 we get the value of H as \left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]

Step 5; Now to find the value of m x H we need to multiply the value of \frac{25}{2} with the matrix \left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]

Step 6; Multiplying we get the matrix m x H = [ -25  \frac{75}{2}  \frac{-25}{2} ]

8 0
3 years ago
PLEASE! 10 POINTS! For what number A does the equation 3Ax - 24 = 5x - 9 + x have no solutions for x?
Gala2k [10]

Answer:

3Ax-6x = 15

3x(A-2)=15

If A were 2, the left side of the equation would be 0 and it wouldn't equal 15 no matter what the value of x is. So A is 2

6 0
3 years ago
Let f be defined as shown.<br> What is f^-1(1)?
FinnZ [79.3K]

Answer:

From the above image when the input of f(x) is 9 the output is 1

So f^-1(1) is just the reverse when the input is 1 the output is 9

So f^-1(1) = 9

Hope this helps

6 0
3 years ago
What is the vertex form of the parabola whose standard form equation is y=5x^2-30x+49
agasfer [191]

Answer:

The vertex is (3,4)

Step-by-step explanation:

To convert a quadratic from  

y = a x 2 + b x + c

form to vertex form,

y = a ( x − h ) 2 + k , you use the process of completing the square.

First, we must isolate the  x

terms:

y − 49 = 5 x 2 − 30 x + 49 − 49

y − 49 = 5 x 2 − 30 x

We need a leading coefficient of  1

for completing the square, so factor out the current leading coefficient of 2.

y − 49 = 5 ( x 2 − 6 x )

Next, we need to add the correct number to both sides of the equation to create a perfect square. However, because the number will be placed inside the parenthesis on the right side we must factor it by  

2

on the left side of the equation. This is the coefficient we factored out in the previous step.

y − 49 + ( 5 ⋅ ? ) = 5 ( x 2 − 6 x + ? )

<- Hint:  

62 = 3 ;  3 ⋅ 3 = 9

y − 49 + ( 5 ⋅ 9 ) = 5 ( x 2 − 6 x + 9 )  

y− 49 + 45 = 5 ( x 2 − 6 x + 9 )

y − 4 = 5 ( x 2 − 6 x + 9 )

Then, we need to create the square on the right hand side of the equation:

y − 4 = 5 ( x − 3 ) 2

Now, isolate the  y  term:

y − 4 + 4 = 5 ( x − 3 ) 2 + 4

y − 0 = 5 ( x − 3 ) 2 + 4

y − 0 = 5 ( x − 3 ) 2 + 4

The vertex is:  

( 3 , 4 )

7 0
3 years ago
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