Answer:
Length of the box is 8 inches while the width is 5 inches
Step-by-step explanation:
The question here says that a candy company plans to hang posters of a new product in supermarkets. The product is a box of premium chocolates. The art team made a scale drawing of the top of the box using a scale of 3 inches to 1 inch. The length of the scale drawing of the box is 24 inches, and its width is 15 inches. We are now asked to find the actual dimensions of the top of the chocolate box
Since the scale drawing measures 24 inches in length and 15 inches in width
And we need to remember that that the scale drawing to the actual dimensions of the package is 3:1
The scale drawings measure length 24 inches. This means that for every 1 inch of the candy box,3 inches scale drawing is taken.
If the scale drawing is 24,the actual length is
24/3 = 8 inches
Now do same for width which has a scale drawing of 15 inches,and it will have
15/3 = 5 inches
The length and the width of the chocolate box measures 8 inches by 5 inches
4x4x4x4x4 and 4^5
answer
last one
Answer:
2nd answer from the top: 3a-b dived by 4
Step-by-step explanation:
Answer:
Step-by-step explanation:
For equating the equations, you get
x2 + kx - 3x + 4 = 0 eq1
Setting the derivative of f(x) equal to 3 yields
f'(x) = 3
2x + k = 3 eq2
Now we substitute the value of k from eq2 into eq1.
x2 + x(3 - 2x) - 3x + 4 = 0
Solve for x from this equation. Then plug in the value of x into eq2 to solve for k
