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djyliett [7]
3 years ago
6

How is an outlier related to a cluster (on a graph) ?

Mathematics
1 answer:
Dmitrij [34]3 years ago
4 0
A cluster in data points have similar numerical values while a outlier is a data point that is either smaller or bigger than the next data point on the graph. I hope this gives a better understanding... 
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Seven subtracted from n is 18​
Vikentia [17]

Answer:

25

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
in a particular class of 23 students, 18 are men. what fraction of the students in the class are men?k
Mademuasel [1]
It gave you the answer for men they said their were 18 men out of 23 so are they asking for women or actually men cause if it was that it would be 18/23
7 0
3 years ago
Which situation is best represented by the equation? 35p + 129.50 = 479.50
Ksivusya [100]

Answer:

A

Step-by-step explanation:

this is because we don't know how many trainers she goes to, so the cost will be 35p. and then include the registration fees she pays.

5 0
3 years ago
What is the answer to (x-4)-(-6+x) ?
Likurg_2 [28]
X - 4 +6 -x
x - x = -2

0 = -2

No solution
5 0
3 years ago
Read 2 more answers
(I've been trying to figure this out for 3 days and I really need help)
liq [111]

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

1)

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7

2)

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55

3)

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

4)

pretty much the same thing, we get the volume of the cone and its top, add them up.

\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^

8 0
3 years ago
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