H = 5 + ut - 16t^2
When the balls falls back to the ground, h = 0
0 = 5 + 3.2u - 16(3.2)^2
0 = 5 + 3.2u - 163.84
0 = 3.2u - 158.84
3.2u = 158.84
u = 158.84/3.2 = 49.6 ft/s
Required equation is
h = 5 + 49.6t - 16t^2
Answer:
At a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would travel 1,333 km.
Step-by-step explanation:
If a kangaroo hops 2 kilometers in 3 minutes, to calculate how much distance this animal hops in 2 minutes, the following calculation should be performed:
2 km / 3 min = 0.666 km per minute (2/3 x 2)
0.666 km per minute x 2 minutes = 1.333 kilometers in 2 minutes (0.666 x 2)
Therefore, at a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would hop 1,333 km.
You need to set up a linear graph. One side with gallons and the other with dollars. Point 1 will be at (1500, 2.10). Point 2 (1300, 2.95). Draw a straight line through these points in your graph and your graph will then give you the answers to your other questions.
Answer: 5/8
Step-by-step explanation:
