The height is 9.875 feet from which the goalkeeper catches the ball.
The player kicks soccer from a height of 2 feet
x = 0 and y = 2
Maximum height of 20 feet after traveling 40 feet
x = 40, y = 20
So let y = a(x - 40)² + 20 ( the path of parabola)
Since x = 0 , y = 2
So, 2 = a(0 - 40)² + 20
2 = 1600a + 20
-18 = 1600a
a = - 9/800
Thus, y = -9/800(x - 40)² + 20
Since the soccer is caught by the goalkeeper 70 feet from where it was kicked
x = 70
So at this time,
y = -9/800 ( 70 - 40)² + 20
= -9/800 × 900 + 20
= - 81/8 + 20
= 79/ 8
= 9.875 feet
Therefore the height at which the goalkeeper catches the ball is 9.875 feet.
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Answer:
208
Step-by-step explanation:
8*8=64
9*8/2=36
36*4=144
144+64=208
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we are given
DEF is a line
so, sum of angles must be 180
angle(DEG)+angle(GEF)=180
now, we can plug values
.........Answer
vertically opposite angle must be equal
angle(GEF)=angle(DEH)
now, we can plug values
now, we can plug x=16
...................Answer
Answer:
T, S, U
Step-by-step explanation:
