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4 years ago

Graph the circle which is centered at (4,6), and which has the point (2,6) on it.

1 answer:

8 0

Given the distance between the center and the point along the circumference , we can determine that the radius of the circle is 2. From that you can find other base points along the circle.

Hope this helps :), not really sure what you were asking!

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A rocket takes off from a height of 30 feet with an initial velocity of 150 ft /sec. The equation that models the path that the

algol13

Answer:

The rocket will hit the floor at 9.57 seconds

Step-by-step explanation:

Given

$G(x) = -16x^2 + 150x + 30$

Take off height = 30ft

Initial velocity= 150ft/s

Required [Missing from the question]

Time to hit the ground

The rocket will hit the ground at:

$G(x) = 0$

So, we have:

$0 = -16x^2 + 150x + 30$

Rewrite as:

$16x^2 - 150x - 30=0$

Solve using quadratic formula, we have:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where:

$a= 16\\ b = -150\\ c = -30$

So, we have:

$x = \frac{-(-150) \± \sqrt{(-150)^2 - 4*16*(-30)}}{2*16}$

$x = \frac{150 \± \sqrt{22500 +1920}}{32}$

$x = \frac{150 \± \sqrt{24420}}{32}$

$x = \frac{150 \± 156.27}{32}$

Split:

$x = \frac{150 + 156.27}{32}\ or\ \frac{150 - 156.27}{32}$

$x = \frac{306.27}{32}\ or\ \frac{-6.27}{32}$

Time cannot be negative;

So:

$x = \frac{306.27}{32}$

$x = 9.57$

<em>Hence, the rocket will hit the floor at 9.57 seconds</em>

3 0

3 years ago

Angle 0 is in the second quadrant, and sin 0=3/5

Aneli [31]

ANSWER

The value of theta in the second quadrant is,

$143.1 \degree$

EXPLANATION

The given trigonometric equation is
$\sin( \theta) = \frac{3}{5}$

This implies that,

$\theta= arcsin(\frac{3}{5} )$

This implies that the principal solution is
$\theta = 36.9 \degree$
and it is an angle in the first quadrant.

But the solution we are looking for is an angle in the second quadrant.

This is given by
$180 - \theta = 180 - 36.9 = 143.1 \degree$

8 0

4 years ago

Please hhhhhhhhhhhhhhhhhhhhelllllllpp

lilavasa [31]

If I'm correct ABC, EDC are congruent If the corresponding figure DE was Increased by 175 ft it would no longer be congruent

6 0

3 years ago

By air, the distance from city a to city b is 3008 miles less than the distance from city c to city

ella [17]

The distance from city C to city D is 4,814 miles.

5 0

4 years ago

What is the radius of the incircle of a regular hexagon with a side of 20 cm ?

Kaylis [27]

10√3 cm.
The radius of an incircle of a hexagon is the same measure as the apothem. find the apothem by taking half of the central angle and create a right triangle perpendicular to the side. The central angle is 60 so the angle opposite the side length will be 30. this creates a 30-60-90 triangle with the ratio x:x√3:2x. half the side opposite 30 is 10, so x=10. the base angle of the side is 60 so it will be x√3. plug in 10 for x to get 10√3 cm.

7 0

4 years ago