<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bx%2B1%7D%20%2B%20%5Cfrac%7B4%7D%7Bx%2B4%7D%20-%20%5Cfrac%7B5%7D%7Bx%2B5%3C

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3 years ago

br%3E%0A%7D%20" id="TexFormula1" title=" \frac{1}{x+1} + \frac{4}{x+4} - \frac{5}{x+5
} " alt=" \frac{1}{x+1} + \frac{4}{x+4} - \frac{5}{x+5
} " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Anna11 [10]3 years ago

4 0

[ ( x + 4 )( x + 5 ) + 4( x + 1 )( x + 5) - 5( x + 1 )( x + 4 ) ] / [( x + 1 )( x + 4)( x + 5 )] = ( x^2 + 9x + 20 + 4x^2 + 24x +20 - 5x^2 - 25x - 20) / [( x + 1 )( x + 4)( x + 5 )] =
( - 2x + 20 ) / [( x + 1 )( x + 4)( x + 5 )] = ( - 2)( x - 10) / [( x + 1 )( x + 4)( x + 5 )]

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Inequality <br> Choose all answers that apply

maxonik [38]

Hi there!

»»————-　★　————-««

I believe your answer is:

Option A; $m \leq\frac{3}{5}$

»»————-　★　————-««

Here’s why:

We can use inverse operations to solve for 'm'.

⸻⸻⸻⸻

$\boxed{\text{Solving for 'm':}}\\\\5m+1\leq4\\--------\\\rightarrow 5m + 1 - 1 \leq 4 - 1\\\\\rightarrow 5m\leq3\\\\\rightarrow \frac{5m\leq3}{5}\\\\\rightarrow \boxed{m\leq\frac{3}{5}}$