Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
In order to solve this problem, you need to use a geometric series:

where:
a₁ = first term of the series = 36000
r = common rate = 10% raise, therefore 1.10
n = number of terms = 5
Therefore,
<span>

= 219783.60 $
Luke's total earnings in five years are
<span>
219783.60 $.</span>
</span>
Answer:
20
Step-by-step explanation:
f(x)= x/5
To solve for f(100), we substitute 100 for x everywhere in the equation:
f(100) = (100)/5
f(100) = 20
You do £68.85 - £15.30= (the answer)
Then you do the answer of that divided by 0.85