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Pavlova-9 [17]
3 years ago
9

Harry created a canvas painting on a square canvas. He then placed an order for a new rectangular canvas. The side length of the

old square canvas is x inches. The new canvas he ordered has the same length, but a width 8 inches greater than that of the old canvas. the area of the new canvas is given by the quadratic expression below, where x represent the side length in inches of the old canvas.
x(x+8)
match each expression to the description it models.

Mathematics
1 answer:
sveta [45]3 years ago
8 0

Answer:

1.x^2

2.x+8

3.x

4. 8x

Step-by-step explanation:

Length of old is x inches.

Because it is square we have that area of the old canvas : x^2

When we read : width of new is increased by 8 so : x+8

Length is x.

The difference of areas:

Old canvas : A1=x^2

New canvas : A2=x(x+8)=x^2+8x

Now we can find A2-A1:

x^2+8x-x^2=8x

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Which graph shows the line of best fit for the data
lys-0071 [83]

Answer:

Graph C shows the line of best fit for the data.

Step-by-step explanation:

The line of Graph C is more centered and even than the other ones

4 0
2 years ago
|-9| = |9| true or false.
bogdanovich [222]

Step-by-step explanation:

1) -9 = 9 true/false

the answer is false because negative and positive quite unlike in terms.

2) -(-21) = -21

Using the symbols multiplication rule,

Where,

<h2>+ × + = +</h2><h2>- × - = +</h2><h2>- × + = -</h2><h2>+ × - = -</h2>

Therefore, -(-21) = +21 = 21

⟼ 21 = -21 \sf true / \:  \sout{false}

6 0
2 years ago
Read 2 more answers
Wren’s first display box is 6 inches long, 9 inches wide, and 4 inches high. What is the volume of the display box? Explain your
Black_prince [1.1K]

Answer:

\text{Volume of display box}=216\text{ in}^3    

Step-by-step explanation:

We have been given that Wren’s first display box is 6 inches long, 9 inches wide, and 4 inches high. We are asked to find the volume of display box.

We know that the box is in form of cuboid, so its volume would be length times width times height.

\text{Volume of display box}=6\text{ in}\times 9\text{ in}\times 4\text{ in}

\text{Volume of display box}=216\text{ in}^3

Therefore, the volume of the display box is 216 cubic inches.

7 0
2 years ago
How do I change this into a reduced fraction
Ivahew [28]
4 over 5 is the correct answer
5 0
3 years ago
Read 2 more answers
Use the Quadratic formula to find all real zeros of the 2nd degree polynomial
schepotkina [342]

Answer:

  x ∈ {-5, -1}

Step-by-step explanation:

Here's the solution using the quadratic formula:

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-24\pm\sqrt{24^2-4\cdot 4\cdot 20}}{2\cdot 4}\\\\=\dfrac{-24\pm\sqrt{576-320}}{8}=\dfrac{-24\pm\sqrt{256}}{8}\\\\=\dfrac{-24\pm 16}{8}=-3\pm 2=\{-5,-1\}

The real zeros are -5 and -1.

_____

There are many ways to check your answer. One of them is to look at the given quadratic, which has no changes of sign in its coefficients. (They are all positive.) That means there can be no positive real roots, so already you know that x=0.5 won't work.

Also, the constant in the quadratic is the product of the roots, For your roots, their product is -7/4, so even multiplying by 4 (the leading coefficient in the given quadratic), you don't get anything like 20.

4 0
2 years ago
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