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Pavlova-9 [17]
3 years ago
9

Harry created a canvas painting on a square canvas. He then placed an order for a new rectangular canvas. The side length of the

old square canvas is x inches. The new canvas he ordered has the same length, but a width 8 inches greater than that of the old canvas. the area of the new canvas is given by the quadratic expression below, where x represent the side length in inches of the old canvas.
x(x+8)
match each expression to the description it models.

Mathematics
1 answer:
sveta [45]3 years ago
8 0

Answer:

1.x^2

2.x+8

3.x

4. 8x

Step-by-step explanation:

Length of old is x inches.

Because it is square we have that area of the old canvas : x^2

When we read : width of new is increased by 8 so : x+8

Length is x.

The difference of areas:

Old canvas : A1=x^2

New canvas : A2=x(x+8)=x^2+8x

Now we can find A2-A1:

x^2+8x-x^2=8x

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3 years ago
What are the points for f(x)=3^(x-1)-2
Savatey [412]

Answer:  (0, -1 \frac{2}{3}), (1, -1), (2, 1)

<u>Step-by-step explanation:</u>

Set the exponent equal to zero - <em>that is your anchor point</em>.

Then choose an x-value less than and greater than the anchor point.

\left\begin{array}{c|c|l}&\underline{\quad x\quad }&\underline{\qquad \qquad f(x)\qquad \qquad \qquad \quad }\\\text{less than anchor}&0&3^{0-1}-2=3^{-1}-2=\frac{1}{3}-2 = -1\frac{2}{3}}\\\\anchor\ point&1&3^{1-1}-2=3^{0}-2=1-2 = -1}\\\\\text{greater than anchor}&2&3^{2-1}-2=3^{1}-2=3-2 = 1}\end{array}\right

4 0
3 years ago
_______ is a combination of two functions such that the output from the first function becomes the input for the second function
zmey [24]
B. Dependent function












8 0
3 years ago
If someone could explain what i plug into f??
Alexxx [7]
You are correct with part i with what you did so far, but you need to finish it.
What is function f?

i.
\dfrac{f(9) - f(2)}{9 - 2}

ii.
\dfrac{f(1) - f(0)}{1 - 0}

iii.
\dfrac{f(9) - f(-7)}{9 - (-7)}
3 0
3 years ago
Find the product of 3562 and 4
jekas [21]
Multiply 3562 and 4.

3562 × 4 = 14248

Hope this helps :)
3 0
3 years ago
Read 2 more answers
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