Ask question

Ask question

All categories

3 years ago

8

Carlos ran 7 miles in 57 minutes. How fast did he run each mile ? June runs a little slower then Carlos. She ran one fourth of a

mile in three minutes.How long will it take her to run a full mile?

1 answer:

skad [1K]3 years ago

7 0

57/7=8.14 so Carols ran 1 mile in 8.14 minutes
3*4=12 so June can run 1 mile in 12 minutes

You might be interested in

water stations will be placed every 600 meters of a fifteen kilometer race. how many water stations will be needed?

Snezhnost [94]

1km=1000metres
15km=15000 metres
15000/600=25
25-1=24 (minus the last one)

hope this helps :)

5 0

3 years ago

Read 2 more answers

Please help and will give brainliest.

valkas [14]

Answer:

The battle that resulted in both a Confederate victory and the death of General “Stonewall” Jackson was

Step-by-step explanation:

The battle that resulted in both a Confederate victory and the death of General “Stonewall” Jackson was

6 0

3 years ago

In Spring, Jack trimmed his tree 3 in. Shorter. In the summer he trimmed it 5 more inches. The tree is now 45 in. Tall. How tall

sergejj [24]

Answer: 53 inches

Step-by-step explanation:3+5=8

45+8= 53

7 0

3 years ago

Read 2 more answers

Help me plzzzzzzzzzzzz

blagie [28]

Answer:

d=1.7, b=7.1

Step-by-step explanation:

3√3/3, so √3 is d, which is 1.7, b is 5 x √2, and its 7.07, so 7.1

4 0

3 years ago

PLEASE ANSWER THIS ASAP

Arisa [49]

Answer:

The equation of line passes through $(4,-1)$ and perpendicular to the graph $y=\frac{7}{2}x-\frac{3}{2}$ is $y=\frac{-2x}{7}+\frac{1}{7}$

Step-by-step explanation:

Given point is $(4,-1)$ and equation of line is $y=\frac{7}{2}x-\frac{3}{2}$

Let the slope of line that passes through point $(4,-1)$ is $m_1$

And slope of line $y=\frac{7}{2}x-\frac{3}{2}$ is $m_2=\frac{7}{2}$ . As it is in the form of $y=mx+c$

We know the relation between slope of perpendicular line are given by

$m_1\times m_2=-1\\And\ m_1=\frac{-1}{m_2}$

So, the slope $m_1=\frac{-1}{\frac{7}{2}}=\frac{-2}{7}$

Now, we can write the equation of line having point $(4,-1)$ and slope $\frac{-2}{7}$

$(y-y_1)=m(x-x_1)\\\\(y-(-1))=\frac{-2}{7}(x-4)\\\\y+1=\frac{-2x}{7}-(\frac{2\times -4}{7})\\ \\y+1=\frac{-2x}{7}+\frac{8}{7}\\\\y=\frac{-2x}{7}+\frac{8}{7}-1\\\\y=\frac{-2x}{7}+\frac{8-7}{7}\\\\y=\frac{-2x}{7}+\frac{1}{7}$

So, the equation of line passes through $(4,-1)$ and perpendicular to the graph $y=\frac{7}{2}x-\frac{3}{2}$ is $y=\frac{-2x}{7}+\frac{1}{7}$

3 0

3 years ago