By means of <em>functions</em> theory and the characteristics of <em>linear</em> equations, the <em>absolute</em> extrema of the <em>linear</em> equation f(x) = - 3 · x + 3 are 27 (<em>absolute</em> maximum) for x = - 8 and - 9 (<em>absolute</em> minimum) for x = 4. (- 8, 27) and (4, - 9).
<h3>What are the absolute extrema of a linear equation within a closed interval?</h3>
According to the functions theory, <em>linear</em> equations have no absolute extrema for all <em>real</em> numbers, but things are different for any <em>closed</em> interval as <em>absolute</em> extrema are the ends of <em>linear</em> function. Now we proceed to evaluate the function at each point:
Absolute maximum
f(- 8) = - 3 · (- 8) + 3
f(- 8) = 27
Absolute minimum
f(4) = - 3 · 4 + 3
f(4) = - 9
By means of <em>functions</em> theory and the characteristics of <em>linear</em> equations, the <em>absolute</em> extrema of the <em>linear</em> equation f(x) = - 3 · x + 3 are 27 (<em>absolute</em> maximum) for x = - 8 and - 9 (<em>absolute</em> minimum) for x = 4. (- 8, 27) and (4, - 9).
To learn more on absolute extrema: brainly.com/question/2272467
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First change the mixed number into a fraction greater than one 1 1/2= 3/2, then divide 2 into 3 which results in 1.5
