Answer:
3, 12, 27 and 300
Step-by-step explanation:
Plug n as 1, 2, 3 and 10.
3(1)² = 3
3(2)² = 12
3(3)² = 27
3(10)² = 300
The first method is substitution. This is when the x or y value that is known is substituted into one of the equations. This should be done when you can easily see or find the x or y value.
Example: x = 3, and x + 8y = 30.
The x was given in the first equation (x = 3), and can therefore be substituted into the other equation to find y.
The next method is elimination. This is when you add the two systems together and eliminate either the x values or the y values. This should be done when there are opposite signs of the same number in both equations.
Example: y - 3x = 24, and 2y + 3x = 7
In the first equation you have -3x, and in the second you have 3x. If you were to add the two equations, the x values would cancel out and you would be left with:
y + 2y = 24 + 7
And then you could solve for y.
The last method is to graph both equations and to see at which point the lines intersect.
Answer:
±90
Step-by-step explanation:
√(-225) · √(-36) = (15i)·(6i) = 90i² = 90·(-1) = -90
_____
On the other hand, ...
... √(-225) · √(-36) = √((-225)·(-36)) = √8100 = 90
___
If you consider all the roots at each stage, the result is ±90. Since you're working with complex numbers here, it is reasonable to recognize every number has two square roots.
... √(-225) = ±15i
... √(-36) = ±6i
... √(-225) · √(-36) = (±15i)·(±6i) = ±90i² = ±90
A very simple example is:
What you need to is just distribute x into the parenthesis, so once x times the first term (a) and once x times the second term (b)
I hope you got
the idea
Answer:
4261
Step-by-step explanation:
8522/2
2*4261=8522
long division
