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3 years ago

... Are these fractions equivalent or nonequivalent? 1/11 2/22

Mathematics

2 answers:

viva [34]3 years ago

7 0

Answer:

Equivalent

Step-by-step explanation:

1/11 times 2=2/22

2/22 divided by 2=1/11

(hope this helps-ty for the points :P)

djyliett [7]3 years ago

4 0

Answer:

equivalent

Step-by-step explanation:

is you divide both 2 and 22 by 2... you get 1/11

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Someone please help!!!!<br> 6+2/3x>12-1/3x

attashe74 [19]

Answer:

the answer is x>6

Step-by-step explanation:

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3 years ago

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Selma uses a jogging trail that runs through a park near her home. The trail is a loop that is of a mile long. On Monday, Selma

Dmitry [639]

If she ran one mile in an hour wouldn't that mean her unit rate is one mile per hour? I think that's right but ask your teacher for reinsurance.

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Find the value of 3a^2+2b, If a=3 and b = 4.<br><br>An explanation would be great.

vichka [17]

Answer:

=35

Step-by-step explanation:

3(3) ^2 + 2(4)

= 3(9) + 8

= 35

Where you see a, substitute with 3 and where you see b, substitute with 4

Just follow the steps above.

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2 years ago

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Please help with these

kherson [118]

The answers are as follows.

a. 9x

In order to get this, you need to reevaluate 64 as a base of 4. Since 64 is equal to 4^3, we can rewrite the right side as

64^3x = (4^3)^3x = 4^9x

Which gives you the first answer.

b. 10

Similar to the first problem, we need to express 16 as a base of 2. 2^4 is equal to 16, so we use that in it's place and simplify.

16^5/2 = (2^4)^5/2 = 2^20/2 = 2^10

c. Sqrt(7.31)

This one is more simple. Raising something to a 1/2 power (.5) is the same as taking the square root.

4 0

3 years ago

Based on historical data, your manager believes that 26% of the company's orders come from first-time customers. A random sample

scoundrel [369]

Answer:

$\hat p \sim N( p, \sqrt{\frac{p (1-p)}{n}})$

And we can use the z score formula given by:

$z = \frac{\hat p -\mu_p}{\sigma_p}$

And if we find the parameters we got:

$\mu_p = 0.26$

$\sigma_p = \sqrt{\frac{0.26(1-0.26)}{158}} = 0.0349$

And we can find the z score for the value of 0.4 and we got:

$z = \frac{0.4-0.26}{0.0349}= 4.0119$

And we can find this probability:

$P(z>4.0119) = 1-P(z$

And if we use the normal standard table or excel we got:

$P(z>4.0119) = 1-P(z$

Step-by-step explanation:

For this case we have the following info given:

$p = 0.26$ represent the proportion of the company's orders come from first-time customers

$n=158$ represent the sample size

And we want to find the following probability:

$p(\hat p >0.4)$

And we can use the normal approximation since we have the following two conditions:

1) np = 158*0.26 = 41.08>10

2) n(1-p) = 158*(1-0.26) = 116.92>10

And for this case the distribution for the sample proportion is given by:

$\hat p \sim N( p, \sqrt{\frac{p (1-p)}{n}})$

And we can use the z score formula given by:

$z = \frac{\hat p -\mu_p}{\sigma_p}$

And if we find the parameters we got:

$\mu_p = 0.26$

$\sigma_p = \sqrt{\frac{0.26(1-0.26)}{158}} = 0.0349$

And we can find the z score for the value of 0.4 and we got:

$z = \frac{0.4-0.26}{0.0349}= 4.0119$

And we can find this probability:

$P(z>4.0119) = 1-P(z$

And if we use the normal standard table or excel we got:

$P(z>4.0119) = 1-P(z$

8 0

3 years ago