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TEA [102]
3 years ago
13

Describe the value of the 9 in 926,415 use at least 2 terms from the word list in your explanation

Mathematics
1 answer:
Sedbober [7]3 years ago
8 0

Answer:

The value of 9 in 926,415 is nine hundred thousands

Step-by-step explanation:

* Lets explain how to write a number in the expand form

- Expand form is a way of writing numbers to see the math value

 of individual digits

- Ex: the expand form of 23,456 is 20,000 + 3,000 + 400 + 50 + 6

- Place value is the value represented by a digit in a number

- Ex: the place value of 5 in 250 is tens

* <em>Lets solve the problem</em>

- The number is 926,415

- The number formed from 6 digits

- The expand form of the number is:

  926,415 = 900,000 + 20,000 + 6,000 + 400 + 10 + 5

- <em>Lets write the place value of each digit</em>

# The place value of 5 is ones

# The place value of 1 is tens

# The place value of 4 is hundreds

# The place value of 6 is thousands

# the place value of 2 is ten thousands

# The place value of 9 is hundred thousands

∴  The place value of 9 in the number is hundred thousands

∴ The value of 9 in 926,415 is nine hundred thousands

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4. Find the standard from of the equation of a hyperbola whose foci are (-1,2), (5,2) and its vertices are end points of the dia
Ad libitum [116K]

The <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

<h3>How to find the standard equation of a hyperbola</h3>

In this problem we must determine the equation of the hyperbola in its <em>standard</em> form from the coordinates of the foci and a <em>general</em> equation of a circle. Based on the location of the foci, we see that the axis of symmetry of the hyperbola is parallel to the x-axis. Besides, the center of the hyperbola is the midpoint of the line segment with the foci as endpoints:

(h, k) = 0.5 · (- 1, 2) + 0.5 · (5, 2)

(h, k) = (2, 2)

To determine whether it is possible that the vertices are endpoints of the diameter of the circle, we proceed to modify the <em>general</em> equation of the circle into its <em>standard</em> form.

If the vertices of the hyperbola are endpoints of the diameter of the circle, then the center of the circle must be the midpoint of the line segment. By algebra we find that:

x² + y² - 4 · x - 4 · y + 4= 0​

(x² - 4 · x + 4) + (y² - 4 · y + 4) = 4

(x - 2)² + (y - 2)² = 2²

The center of the circle is the midpoint of the line segment. Now we proceed to determine the vertices of the hyperbola:

V₁(x, y) = (0, 2), V₂(x, y) = (4, 2)

And the distance from the center to any of the vertices is 2 (<em>semi-major</em> distance, a) and the semi-minor distance is:

b = √(c² - a²)

b = √(3² - 2²)

b = √5

Therefore, the <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

To learn more on hyperbolae: brainly.com/question/27799190

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5 0
2 years ago
Please help...........
enyata [817]
On what i need to see what you are talking bout so maybe i can answer it thank u please
7 0
3 years ago
What is the sequence of second differences for ax +b?
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Answer:

ZERO

Step-by-step explanation  

Write the given function as

F(x) = ax + b

i.e Y = ax + b

now differentiate Y with respect to X

dY/dX = d (ax + b)/ dx

dY/dX = a

now again differentiate this function with respect to x

so,  d^2Y/dX^2 = d^2 (a)/dX^2

                         = 0 (ZERO)

note: differentiation of constant function is zero

4 0
3 years ago
X+y+z =4
cestrela7 [59]
<span><span> <span>Akar akar persamaan kuadrat 2x² - 3x -1 = 0 adalah x1 dan x2. Persamaan kuadrat baru yang akar akarnya satu lebih kecil dari dua kali akar akar persamaan kuadrat di atas adalah ........</span></span><span><span><span>A.x² - x - 4 = 0</span><span>B.x² + 5x - 4 = 0</span><span>C.x² - x + 4 = 0</span></span><span><span>D.x² + x + 4 = 0</span><span>E.x² - 5x - 4 = 0</span></span></span><span>Jawaban : A
Penyelesaian : 
Akar-akar persamaan lama :  x1 dan x2
                                             
Akar-akar persamaan baru :  xA dan xB
                                             xA = 2x1 - 1
                                             xB = 2x2 - 1
                                             xA + xB  = (2x1 - 1) + (2x2 - 1)
                                                           = 2 (x1 + x2) - 2
                                                           = 2 () - 2
                                                           = 3 - 2
                                              xA + xB = 1
    
                                              xA . xB = (2x1 - 1) (2x2 - 1)
                                                          = 4 x1.x2 - 2(x1 + x2) + 1
                                                          = 4.(-) - 2() + 1
                                                          = -2 - 3 + 1
                                              xA . xB = -4
    
Jadi persamaan kuadrat baru : x² - (xA + xB)x + xA . xB = 0
                                              x² - x - 4 = 0

</span></span>
4 0
4 years ago
Simplify the expression -4x^2(3x − 7).
satela [25.4K]

Answer:

Step-by-step explanation:

Simplify the expression -4x^2(3x − 7).

A. -12x^3 + 28

<h2>B. -12x^3 + 28x^2<= your answer</h2>

C. -12x^3 − 28

D. -12x^3 − 28x^2

5 0
3 years ago
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