<span>Fundamentally, the cell would cease to function and possibly die. Proteins are used for cellular repairing and chemical processes. Ribosomes are one of the most important organelles in the cell, mostly part of the rough endoplasmic reticulum. It manufactures enzymes such as proteins which will be utilized by many organelles in the cell. Microtubules are one, responsible for the framework and acts as a skeleton of the cell –cytoskeleton needs proteins, also cytoplasm and other organelles of the cell. For a prokaryote or a eukaryote cell to survive, they need protein.<span>
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Explanation:
not interested............
Answer:
It is a single stranded DNA since adenine percentage is not equal to that of thymine and the percentage of guanine is not equal to cytosine.
Explanation:
According to Chargaff rule, the amount of adenine in a double-stranded DNA is always equal to that of thymine. This is due to the fact that adenine pairs with thymine in a double-stranded DNA. Likewise, the amount of guanine is always equal to that of cytosine in a double-stranded DNA.
The percentage of four types of bases in the genome of the virus does not follow the Chargaff rule and hence, it is a single-stranded DNA.
At each different stage of development, the young will eat different foods. The larvae may eat stems, the nymph and adult may eat leaves.
Answer:
No, a blood test could not eliminate the father.
Explanation:
The mother had B type blood, so the possible genotypes are BB and BI. The father had A type blood, so the possible genotypes are AA and AI. The child had O type blood, so the only possible genotype is II. If the mother has the genotype BI and the father has the genotype AI, then there is a 25% chance the child will have the blood type O, or II (I used a punnet square with the genotypes BI and AI to solve this.)