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blondinia [14]
3 years ago
15

The DVD player shows the time of day as 1:43.

Mathematics
1 answer:
steposvetlana [31]3 years ago
3 0

Answer:

The answer is 2:36

Step-by-step explanation:

The answer is 2:36 because 1:43 plus 56 minutes later would be 2:36

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its the first one

Step-by-step explanation:

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Answer:

$50.00

Step-by-step explanation:

I did this. 18.95+2.95+15.64+5+7.46. It equaled 50 so fifty dollars is your answer.

7 0
2 years ago
Dennis and Connie purchased a radio for $128. Dennis paid $36 more than Connie. How much did each pay?
never [62]

Answer:

Dennis paid $82 and Connie paid $46.

Step-by-step explanation:

We can set up an equation by putting in variables, c representing how much Connie paid. Since we know that Dennis paid $36 more, we will also factor that in the equation.

c + c + 36 = 128

Where c + 36 represents the amount Dennis paid, and 128 represents the total amount paid as given in the question. We can start by adding like terms. 2c + 36 = 128

Now, we can subtract 36 from each side,

2c + 36 - 36 = 128 - 36

2c = 92

Divide each side by two,

2c/2 = 92/2

c = 46

Now, to make sure this is correct, let's substitute our c for 46 in our equation:

46 + 46 + 36 = 128

92 + 36 = 128

128 = 128

Therefore, our equation is correct, and Dennis paid $82 while Connie paid $46.

6 0
3 years ago
Use the exponential decay​ model, Upper A equals Upper A 0 e Superscript kt​, to solve the following. The​ half-life of a certai
Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

A=A_0 e^{kt}

Where,

A_0 = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = \frac{A_0}{2},

i.e.

\frac{A_0}{2}=A_0 e^{19k}

\frac{1}{2} = e^{19k}

0.5 = e^{19k}

Taking ln both sides,

\ln(0.5) = \ln(e^{19k})

\ln(0.5) = 19k

\implies k = \frac{\ln(0.5)}{19}\approx -0.03648

Now, if the substance to decay to 78​% of its original​ amount,

Then A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0

0.78 A_0=A_0 e^{-0.03648t}

0.78 = e^{-0.03648t}

Again taking ln both sides,

\ln(0.78) = -0.03648t

-0.24846=-0.03648t

\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7

Hence, approximately the substance would be 78% of its initial value after 7 years.

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3 years ago
The amounts that two partners invested in a new business are given in the table above. If the partners share the profits in the
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They cant it with the money
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