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Irina18 [472]
3 years ago
6

Solve the system of equations. y=3x y=x^2-10

Mathematics
2 answers:
puteri [66]3 years ago
5 0

Answer:

y=3x.........1

y=x^2-10.......2

substituting value of eq 1 to 2

3x=x^2-10

x^2-10-3x=0

x^2-3x-10=0

x^2-5x+2x-10=0

X(x-5)+2(x-5)=0

(x-5)(X+2)=0

then

X=5 or X=-2

again

y=??

when X=5

y=3×5=15

when X=-2

y=-6

Burka [1]3 years ago
5 0

Answer:

(-2, - 6) and (5,15) thats the answer hope that helps

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5.) it costs $12 to attend a golf clinic with a local pro
Volgvan

Answer:

You can buy 6 buckets

Step-by-step explanation:

30=-12+3x

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you can buy 6 buckets

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makkiz [27]
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PLEASE HELP
SVETLANKA909090 [29]

Answer:

Hill 1: F(x)  = -(x + 4)(x + 3)(x + 1)(x - 1)(x - 3)(x - 4)

Hill 2: F(x)  = -(x + 4)(x + 3)(x + 1)(x - 1)(x - 3)(x - 4)

Hill 3: F(x) = 4(x - 2)(x + 5)

Step-by-step explanation:

Hill 1

You must go up and down to make a peak, so your function must cross the x-axis six times. You need six zeros.

Also, the end behaviour must have F(x) ⟶ -∞ as x ⟶ -∞ and F(x) ⟶ -∞ as x⟶ ∞. You need a negative sign in front of the binomials.

One possibility is

F(x)  = -(x + 4)(x + 3)(x + 1)(x - 1)(x - 3)(x - 4)

Hill 2

Multiplying the polynomial by -½ makes the slopes shallower. You must multiply by -2 to make them steeper. Of course, flipping the hills converts them into valleys.

Adding 3 to a function shifts it up three units. To shift it three units to the right, you must subtract 3 from each value of x.

The transformed function should be

F(x)  = -2(x +1)(x)(x -2)(x -3)(x - 6)(x - 7)

Hill 3

To make a shallow parabola, you must divide it by a number. The factor should be ¼, not 4.

The zeroes of your picture run from -4 to +7.

One of the zeros of your parabola is +5 (2 less than 7).

Rather than put the other zero at ½, I would put it at (2 more than -4) to make the parabola cover the picture more evenly.

The function could be

F(x) = ¼(x - 2)(x + 5).

In the image below, Hill 1 is red, Hill 2 is blue, and Hill 3 is the shallow black parabola.

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3 years ago
Kiara desea contratar el servicio de una línea telefónica con internet para realizar sus clases virtuales. Si el costo de una lí
ArbitrLikvidat [17]

a) Kiara ha adquirido una línea de telefonía móvil con internet a un Coste Fijo de 10 soles y un Tasa de Consumo de 1,5 soles por hora consumida.

b) El Coste total por 48 horas de consumo de la línea telefónica con internet es 82 soles.

a) Nota - Puesto que la ecuación que describe el Coste ya existe en el enunciado, entonces se entiende el verbo <em>"Expresa"</em> como <em>"Describa en sus propias palabras"</em>.

Como puede apreciarse el Coste de la línea telefónica móvil aumenta linealmente con el Tiempo de consumo por parte del usuario. En consecuencia, la función de Coste queda definida como sigue:

C(t) = C_{o} + r\cdot t (1)

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Entonces, tenemos que Kiara ha adquirido una línea de telefonía móvil con internet a un Coste Fijo de 10 soles y un Tasa de Consumo de 1,5 soles por hora consumida.

b) Una característica de las Funciones Lineales es que tanto su Dominio como Rango comprenden al Conjunto de todos los Números Reales, al ser de Pendiente constante esta Función.

Por tanto, el Dominio y el Rango de la Función en cuestión es el Conjunto de todos los Números Reales.

c) Si sabemos que C_{o} = 10, r = 1,5 y t = 48, entonces el Coste Total por concepto de 48 horas de consumo es:

C(48) = 10 + 1,5\cdot (48)

C(48) = 82

El Coste total por 48 horas de consumo de la línea telefónica con internet es 82 soles.

Invitamos a ver este problema sobre Costes: brainly.com/question/15723794

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