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2 years ago

Solve the system of equations. y=3x y=x^2-10

Mathematics

2 answers:

puteri [66]2 years ago

5 0

Answer:

y=3x.........1

y=x^2-10.......2

substituting value of eq 1 to 2

3x=x^2-10

x^2-10-3x=0

x^2-3x-10=0

x^2-5x+2x-10=0

X(x-5)+2(x-5)=0

(x-5)(X+2)=0

then

X=5 or X=-2

again

y=??

when X=5

y=3×5=15

when X=-2

y=-6

Burka [1]2 years ago

5 0

Answer:

(-2, - 6) and (5,15) thats the answer hope that helps

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jek_recluse [69]

Answer/Step-by-step explanation:

Recall: if two figures are similar, we know that the ratio of their areas = the square of the ratio of their corresponding sides

Apply this knowledge to solve the problems given.

✔️Problem 1 (4-sided polygon):

Let the missing area be x cm²

Therefore,

$\frac{x}{9} = \frac{8^2}{4^2}$

$\frac{x}{9} = \frac{64}{16}$

$\frac{x}{9} = 4$

Multiply both sides by 9

x = 9*4

x = 36 cm²

✔️Problem 2 (3-sided polygon):

Let the missing area be y cm²

Therefore,

$\frac{y}{240} = \frac{8^2}{32^2}$

$\frac{y}{240} = \frac{64}{1,024}$

$\frac{y}{240} = \frac{1}{16}$

Multiply both sides by 240

y = ¹/16 × 240

y = 15 cm²

✔️Problem 3 (5-sided polygon):

Let the missing area be z cm²

Therefore,

$\frac{z}{40} = \frac{3^2}{2^2}$

$\frac{z}{40} = \frac{9}{4}$

Multiply both sides by 40

$z = \frac{9}{4} * 40$

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z = 90 cm²

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