Question

Solve the system of equations. y=3x y=x^2-10

Answer 1

Answer:

y=3x.........1

y=x^2-10.......2

substituting value of eq 1 to 2

3x=x^2-10

x^2-10-3x=0

x^2-3x-10=0

x^2-5x+2x-10=0

X(x-5)+2(x-5)=0

(x-5)(X+2)=0

then

X=5 or X=-2

again

y=??

when X=5

y=3×5=15

when X=-2

y=-6

Answer 2

Answer:

(-2, - 6) and (5,15) thats the answer hope that helps