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alexandr1967 [171]
3 years ago
13

SOMEONE PLEASE HELP!!!

Mathematics
1 answer:
yuradex [85]3 years ago
8 0

Answer:

This is an arithmetic sequence with a common difference <em>d</em> of -5

Step-by-step explanation:

When you find out <em>d</em>, you realize the difference between the numbers to be -5. Since it is <em>d</em> and not common ratio <em>r</em>, it is an arithmetic sequence.

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What is the vertex of the graph of the function y=-2x^2+16x-15
andrey2020 [161]
<u>X - Vertex</u>
Vertex = -\frac{b}{2a} \\Vertex = -\frac{16}{2(-2)} \\Vertex = -\frac{16}{-4} \\Vertex = 4

<u>Y - Vertex</u>
y = -2x^{2} + 16x - 15 \\y = -2(4)^{2} + 16(4) - 15 \\y = -2(16) + 64 - 15 \\y = -32 + 64 - 15 \\y = 32 - 15 \\y = 17

Vertex:(4, 17)
8 0
3 years ago
Please help me !!!!!!!!!!!!!!!!!!
Vitek1552 [10]

Answer:

11.27

Step-by-step explanation:

8 0
3 years ago
What are the potential solutions of log4x+log4(x+6)=2?
lions [1.4K]

The potential solutions of log_4x+log_4(x+6)=2 are 2 and -8.

<h3>Properties of Logarithms</h3>

From the properties of logarithms, you can rewrite logarithmic expressions.

The main properties are:

  • Product Rule for Logarithms - log_{b}(a*c)=log_{b}a+log_{b}c
  • Quotient Rule for Logarithms - log_{b}(\frac{a}{c} )=log_{b}a-log_{b}c
  • Power Rule for Logarithms - log_{b}(a^c)=c*log_{b}a

The exercise asks the potential solutions for  log_4x+log_4(x+6)=2. In this expression you can apply the Product Rule for Logarithms.

                                  log_4x+log_4(x+6)=2\\ \\ x*(x+6)=4^2\\ \\ x^2+6x=16\\ \\ x^2+6x-16=0

Now you should solve the quadratic equation.

 

 Δ=b^2-4ac=36-4*1*(-16)=36+64=100. Thus, x will be x_{1,\:2}=\frac{-6\pm \:\sqrt{100} }{2\cdot \:1}=\frac{-6\pm \:10}{2}. Then:

x_1=\frac{-6+10}{2}=\frac{4}{2} =2\\ \\ \:x_2=\frac{-6-10}{2}=\frac{-16}{2} =-8

The potential solutions  are 2 and -8.

Read more about the properties of logarithms here:

brainly.com/question/14868849

4 0
2 years ago
suppose a farmer encloses a rectangular region of a land next to a river. fencing will be used on 3 sieds, and none is needed al
nexus9112 [7]

Answer:

Dimensions :

x (the longer side, only one side with fence )   =  90  ft

y ( the shorter side two sides with fence )        =  45  ft

Total fence used   45 * 2  +  90    =  180 ft

A(max)  =  

Step-by-step explanation: If a farmer has 180 ft of fencing to encloses a rectangular area with fence in three sides and the river on one side, the farmer surely wants to have a maximum enclosed area.

Lets call "x" one the longer side  ( only one of the longer side of the rectangle will have fence, the other will be along the river and won´t need fence. "y" will be the shorter side

Then we have:

P = perimeter  =  180  =  2y  +  x        ⇒   y  =  ( 180 - x )  / 2        (1)

And   A (r)   =  x * y

A(x)   =  x  *  ( 180 - x ) /2       ⇒   A(x)   = (180/2) *x   -  x² / 2

Taking derivatives on both sides of the equation :

A´(x)   =  90   -  x    

Then if    A´(x)   =  0   ⇒        90   -  x    =  0     ⇒   x  =  90 ft

and from :       y  =  ( 180 - x )  / 2     ⇒     y  =  90/2

y  =  45  ft

And

A(max)  =  90 * 45    =  4050  ft²

4 0
3 years ago
I(1, 1) and J (-3,-3)<br> Find the midpoint of the line segment
Pavlova-9 [17]
The Answer is (-1,-1)
4 0
3 years ago
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