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ANTONII [103]
3 years ago
5

On the classic gameshow The Price Is Right, contestants must guess the price of an object (guesses are distinct). The winner is

determined to be the person whose bid is closest to the correct price, but without going over. For example, if the guesses were Alice 430 Bob 538 Carol 487 David 550 and the true price were 520, then Carol has the winning bid with 487. With the same bids as above, if the actual price had been 420, then no one would win, as everyone bid too high. Your job is to implement a function with signature judge (auction, price) in which auction is a nonempty list of (person, guess) tuples and price is the actual price. The function must return the name of the winning person (or None, if no one wins). For example, the first scenario above might be expressed as judge( [('Alice', 430), ('Bob', 538), ('Carol', 487), ('David', 550)], 520) and the string 'Carol' should be returned as the winner. Your function may assume that all parameters are valid. []

Computers and Technology
1 answer:
Kruka [31]3 years ago
3 0

Answer:

The program code is in explaination

Explanation:

Program code below.

def judge(auction,price):

"""

Function: Returns Name who auctioned very near to give price

Input :

auction : list of tuples

price : auction price

output: returns name of best auction amount holder

"""

diff = [] #storing differences between auctionist amount and price

count = 0

for each_pair in auction:

if each_pair[1]<=price:

diff.append(price-each_pair[1])

else:

count+=1

diff.append(each_pair[1])

if count == len(auction): #check for if no one have auctioned good amount

return None

else:

more_possibility_index = diff.index(min(diff)) #finding index of best amount from diff list

return auction[more_possibility_index][0]

auction = [('Alice',430),('Bob',538),('Carol',487),('David',550)]

price = 520

print(judge(auction,price))

I kept the output at the attachment.

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Help with some questions. Thank you!
Oksana_A [137]

Answer:

1. E: II and III only

2. A: (int)(Math.random() * (upper − lower) ) + lower

3. A: The value of answer is N

4. E: while( !(userGuess == secretNumber) && numGuesses <= 15 )

5. C: 21

Explanation:

1. Which of the following is equivalent to while(userGuess != secretNumber)?

I. while( userGuess < secretNumber && userGuess > secretNumber)  

NO - This will test until the userGuess is smaller AND greater than the secretNumber, at the same time... so that condition will never be true.

II. while( userGuess < secretNumber || userGuess > secretNumber)

YES - This will test the value of userGuess and see if it's smaller OR greater than secetNumber.  So, it will loop until the user guesses right.

III. while( !(userGuess == secretNumber) )

YES, this will negate the match with the secretNumber.  In order words, if it's not a match, it will return true... so the loop will run until it finds a false condition (a match).

As you can see, only II and III are valid.

2.  If the lower limit were inclusive and the upper limit exclusive, which expression would properly generate values for the secret number?

A: (int)(Math.random() * (upper − lower) ) + lower

Since the lower limit is INCLUSIVE, we mustn't add one to the lower limit.  Also, the Math.random() function returns a value that matches our needs; it returns a value between [0,1[ (meaning the 0 is included, but not the 1).

Assuming the (int) caster does return only the integer portion doing a round down of the result, we'll be perfect.

3. What conclusion can be made about the state of the program when the while loop terminates?

while(!answer.equals( "N"))

{.....

A: The value of answer is N

The condition in the loops reads as "While the negation of the answer being 'N', loop".  If the answer equals 'N' then the method should return true... which will be negated by the '!' operator, causing the condition to be false. Thus we know that if the loop ends, the value of answer contains 'N', any other value will keep the loop going.

4. Assuming numGuesses is initialized to 1, how would the while statement be modified to include an extra criterion limiting the number of guesses to 15?

E: while( !(userGuess == secretNumber) && numGuesses <= 15 )

This modified condition will first test to see if the user has guessed the secretNumber (if he has, the first sub-parenthesis will be true... so the left side of the && operator will be false due to the negation operator.  The right side of the && operator will check to see how many tries have been attempted. Since the counter starts at 1, it needs to go up to 15 inclusively... so the <= is the right comparison operator.

5. After execution of the following code segment, what will be displayed?

int x = 1;

while(x < 18)

{

x += 5;

}

System.out.println(x);

C: 21

The x variable is initialized with 1... then enters the loop, in which it is incremented by 5 at each passage.

So after first passage, x = 6

After second passage, x = 11

After third passage, x = 16

After fourth passage, x = 21

Cannot enter the loop again because 21 > 18.

So, it will print out the value of 21.

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strojnjashka [21]

Answer:

import java.util.Scanner;

public class num8 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter month's budget");

       double monthBudget = in.nextDouble();

       double totalExpenses = 0.0;

       double n;

       do{

           System.out.println("Enter expenses Enter zero to stop");

           n = in.nextDouble();

           totalExpenses += n;

       }while(n>0);

       System.out.println("Total expenses is "+totalExpenses);

System.out.println("The amount over your budget is "+ Math.abs(monthBudget-totalExpenses));

   }

}

Explanation:

  • Using Java programming language
  • Prompt user for month's budget
  • Use Scanner class to receive and store the amount entered in a variable
  • Use a do while loop to continuously request user to enter amount of expenses
  • Use a variable totalExpenses to add up all the expenses inside the do while loop
  • Terminate the loop when user enters 0 as amount.
  • Subtract totalExpenses from monthBudget and display the difference as the amount over the budget

6 0
3 years ago
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