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AVprozaik [17]
3 years ago
12

If a filesystem has a block size of 4096 bytes, this means that a file comprised of only one byte will still use 4096 bytes of s

torage. A file made up of 4097 bytes will use 4096 bytes of storage. A file made up of 4097 bytes will use 4096*2=8192 bytes of storage. Knowing this, can you fill in the gaps in the calculate_storage function below, which calculates the total number of bytes needed to store a file of a given size?
1 def calculate_storage(filesize):
2 block_size = 4096
3 # Use floor division to calculate how many blocks are fully occupied
4 full_blocks = ___
5 # Use the modulo operator to check whether there's any remainder
6 partial_block_remainder = ___
7 # Depending on whether there's a remainder or not, return
8 if partial_block_remainder > 0:
9 return ___
10 return ___
11
12 print(calculate_storage(1)) # Should be 4096
13 print(calculate_storage(4096)) # Should be 4096
14 print(calculate_storage(4097)) # Should be 8192
15 print(calculate_storage(6000)) # Should be 8192
Computers and Technology
1 answer:
mars1129 [50]3 years ago
8 0

Answer:

def calculate_storage(filesize):

   block_size = 4096

   full_blocks = filesize // block_size

   partial_block = filesize % block_size

   if partial_block > 0:

       return (full_blocks + 1) * block_size

   return filesize

print(calculate_storage(1))

print(calculate_storage(4096))

print(calculate_storage(4097))

Explanation:

The python program defines the function 'calculate_storage' that calculates the block storage used. It gets the number of blocks used to store the data by making a floor division to get the integer value, then it checks for remaining spaces in the block. If there are spaces left, it adds one to the full_blocks variable and returns the result of the multiplication of the full_blocks and block_size variables.

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Answer:

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   public static void main(String[] args) {

   Scanner in = new Scanner (System.in);

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   }

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Explanation:

This code is implemented in Java.

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3 years ago
write a program that computes an integer's checksum. to compute the checksum, break the integer into its constituent
Serggg [28]

Using the knowledge in computational language in python it is possible to write a code that computes an integer's checksum.

<h3>Writting the code:</h3>

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<em>            r = r*2</em>

<em>            while(r!=0):                            # do the process</em>

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<em>            n=int(n/10)    </em>

<em>        else:                       # if counter is odd position then simple add the digit </em>

<em>            total = total + r       # into total</em>

<em>            n=int(n/10)</em>

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#SPJ1

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The answer is ..........

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