Question

A club has $5$ members from each of $3$ different schools, for a total of $15$ members. How many possible ways are there to arrange a presidency meeting under the following conditions: i. The club must choose one of the $3$ schools at which to host the meeting, and ii. The host school sends $2$ representatives to the meeting, and each of the other two schools sends $1$ representative.
Please answer this correctly, I will mark the person who gets it correct Brainliest.

Answer 1

Answer:

750

Step-by-step explanation:

Pick one of the schools as the host. There are C(5, 2) ways to select the two representatives from that school and C(5, 1) ways to pick a representative from each of the other schools. So once we have selected a host school, there are 10*5*5=250 ways to pick the representatives. However, any of the three schools can be the host, so we need to multiply 250 by 3 to get 750 ways.