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3 years ago

FIST PERSON WHO ANSWERS THIS RECEIVES 30 POINTS!!

2 answers:

7 0

To find the mean, sum up {1,7,12,32,5} (the sum is 57) and divide the result by the count of these numbers (5): 57/5, or 11.4.

To find the median, arrange the set of numbers in ascending order: {1, 5, 7, 12, 32}. Now pick out the middle number: It is 7. This is the median of the data.

The mode is the number that shows up most frequently. In this problem, none of the numbers show up more than once, so this data has no mode.

Summary: mean: 11.4; median: 7

Ksenya-84 [330]3 years ago

6 0

Mean: 11.4

Median: 7

Mode: there isn't one

Mean: 1+5+7+12+32=57 57÷5=11.4

Median: 1, 5, 7, 12, 32. 7 is the middle number.

Mode: there isnt a number that repeats itself.

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Please, Help. the answer isn't 30°

vagabundo [1.1K]

The missing angle of the right triangle ABC has a measure of 30°. (Correct answer: A)

<h3>How to find a missing angle by triangle properties</h3>

Triangles are geometrical figures formed by three sides and whose sum of internal angles equals 180°. There are two kind of triangles existing in this question: (i) Right triangles, (ii) Isosceles triangles.

Right triangles are triangles which one of its angles equals 90° and isosceles triangles are triangles which two of its sides have equal measures.

According to the statement, we know that triangle BQR is an isosceles triangle, whereas triangles ABC, ANB and NBC are right triangles. Based on the figure attached below, we have the following system of linear equations based on right triangles ABC and NBC:

2 · x + 90 + θ = 180 (1)

(90 - x) + 90 + θ = 180 (2)

By equalizing (1) and (2) we solve the system for x:

2 · x = 90 - x

3 · x = 90

x = 30

And by (1) we solve the system for θ:

θ = 180 - 2 · x - 90

θ = 30

The missing angle of the right triangle ABC has a measure of 30°. (Correct answer: A) $\blacksquare$

To learn more on right triangles, we kindly invite to check this verified question: brainly.com/question/6322314

8 0

2 years ago

A, b and c are the sides of a right triangle, where side a is across from angle a, side b is across from angle b, and side c is

Vera_Pavlovna [14]

Find missing length :

a² + b² = c²
c² = 19² + 34²
c² = 1517
c = √1517
c = 38.95 units.

Find missing angle A:

$\dfrac{a}{\sin(a)} = \dfrac{c}{\sin(c)}$

$\dfrac{19}{\sin(a)} = \dfrac{38.95}{\sin(90)}$

$\sin(a) = 0.488$

$a = sin^{-1} (0.488)$

$a = 29.2 \textdegree$

Find Missing B:

$\dfrac{b}{\sin(b)} = \dfrac{c}{\sin(c)}$

$\dfrac{34}{\sin(b)} = \dfrac{38.95}{\sin(90)}$

$\sin(b) = 0.873$

$b = sin^{-1}(0.873)$

$b = 60.8 \textdegree$

Answer: Missing length = 38.95 units ; Missing angles = 29.2° and 60.8°

8 0

3 years ago

(Geometry course question) Explain why it is not possible to construct an equilateral triangle that has

Nutka1998 [239]

Answer:

√3 is irrational

Step-by-step explanation:

The location of the third point of a triangle can be found using a rotation matrix to transform the coordinates of the given points.

<h3 /><h3>Location of point C</h3>

With reference to the attached figure, the slope of line AC is √3, an irrational number. This means the line AC never passes through a point with integer coordinates. (Any point with integer coordinates would be on a line with rational slope.)

<h3>Equilateral triangle</h3>

The line segments making up an equilateral triangle are separated by an angle of 60°. If two vertices are on grid squares, the third must be a rotation of one of them about the other through an angle of 60°. The rotation matrix is irrational, so the rotated point must have irrational coordinates.

The math of it is this. For rotation of (x, y) counterclockwise 60° about the origin, the transformation matrix is ...

$\left[\begin{array}{cc}\cos(60^\circ)&\sin(60^\circ)\\-\sin(60^\circ)&\cos(60^\circ)\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{c}x'\\y'\end{array}\right]$

Cos(60°) is rational, but sin(60°) is not. For any non-zero rational values of x and y, the sum ...

cos(60°)·x + sin(60°)·y

will be irrational.

As in the attached diagram, if one of the coordinates of the rotated point (B) is zero, then one of the coordinates of its image (C) will be rational. The other image point coordinate cannot be rational.