Solve using quadratic formula 1. y=3x^2-x-6 2. y=-5x+7x+3

Mathematics

1 answer:

nignag [31]3 years ago

5 0

My estimated answer for 1 is x=1.59 or x=-1.26 and my exact answer is (in word form) x= 1 plus or minus the square root of 73 over 6. my estimated answer for 2 is x=-0.34 or x=1.74 and my exact answer (in word form) is x= -7 plus or minus the square root of 109 over -10. I took a picture of my work and hopefully you can read it

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lys-0071 [83]

Answer:

ASA

ΔFGH ≅ ΔIHG ⇒ answer B

Step-by-step explanation:

* Lets revise the cases of congruence

- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and

including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ

≅ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

leg of the 2nd right angle Δ

* Lets prove the two triangles FGH and IHG are congruent by on of

the cases above

∵ FG // HI and GH is transversal

∴ m∠FGH = m∠IHG ⇒ alternate angles

- In the two triangles FGH and IHG

∵ m∠FHG = m∠IGH ⇒ given

∵ m∠FGH = m∠IHG ⇒ proved

∵ GH = HG ⇒ common side

∴ ΔFGH ≅ ΔIHG ⇒ ASA

* ASA

ΔFGH ≅ ΔIHG

3 0

3 years ago

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zhuklara [117]

Hey there :)

We know the distance formula is:
D = $\sqrt{(x2-x1)^2+(y2-y1)^2}$

1) Coordinates are: ( -10, -5 ) , ( 8 , 5 )
↓ ↓ ↓   ↓
x₁ y₁ x₂ y₂
We plug in the values
D = $\sqrt{(8 -(-10))^2+(5-(-5))^2}$
  ≈20.59 ≈ 20.6 (nearest tenth)

We do the same for the rest

2) Coordinates are ( 10 , 0 ) , ( -2 , 1 )
D = $\sqrt{(-2-10)^2+(1-0)^2}$
≈ 12.04 ≈ 12.0 (nearest tenth)

3) Coordinates are ( 4 , 8 ) , ( 7 , -8 )
D = $\sqrt{((7-4)^2+(-8-8)^2}$
≈ 16.27 ≈ 16.3 (nearest tenth)

4) Coordinates are ( -10, -4 ) , ( 8 , 8 )
D = $\sqrt{(8-(-10))^2+(8-(-4))^2}$
  ≈ 21.6 (nearest tenth)

5) Coordinates are ( 6 , -3 ) , ( -8 , 9 )
D = $\sqrt{(-8-6)^2 + (9-(-3))^2}$
≈ 18.4 (nearest tenth)

You can find the matching below :)