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Archy [21]
3 years ago
11

Handles-n-Things is a small enterprise company buying new carpet for their office room. The room is 15 ft. wide and 24 ft. long.

The carpeting is sold only in square yards. How many square yards of carpeting will they need? Round your answer to the nearest tenth of a square yard? Area of a rectangle = length x width.
40
Mathematics
1 answer:
Helen [10]3 years ago
4 0

Hey there!

To find the area, we multiply the length by the width! The carpet will cover the area of the room.

24×15=360

But, the carpeting is sold in square yards, not feet. There are three feet in a yard, which means that one yard is 1/3 feet. Since we have 360 square feet, we will divide it by three to get yards.

360/3=120

Therefore, the office would need 120 square yards of carpeting.

Have a wonderful day!

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Jobisdone [24]
Add 2 3/4 and 2 1/2 and you’ll get ur answer. area means total and when u see area, it means add
8 0
2 years ago
Solve for x.<br><br><br><br> 80<br> 22<br> 40<br> 12
kari74 [83]
Use the Pythagorean theorem to solve this problem. So, 81+x^2=1681. ( Pythagorean theorem: a^2+b^2=c^2). x^2=1600. x=40.
4 0
3 years ago
Jensen has an above ground pool in the shape of a regular octagon. Opposite sides are 25 feet apart and each side is 10.4 feet l
bija089 [108]

Answer:

<u>Given</u>: base = 10.4ft, height = 12.5

Area of octagon = 8(1/2 × b × h)

  • 8(1/2 × 10.4 × 12.5)
  • 520ft²

Volume of pool = 520ft² × 3ft

  • 1560ft³

Now, 1 cubic ft takes 7.5 gallons to fill.

Therefore, 1560 cubic ft takes,

  • 1560 × 7.5
  • 11700

So, <u>Correct choice</u> - [D] 11,700.

6 0
3 years ago
Determine how many times larger is 6 x 10^4 than 6 x 10^2
goldfiish [28.3K]

Answer:

100

Step-by-step explanation:

6 . 10^4 = 6 . 10000 = 60000

6 . 10^2 = 6 . 100 = 600

60000 ÷ 600 = 100

8 0
3 years ago
What is the distance from C to D?<br><br> A. 5 units<br> B. 1 unit<br> C. 25 units<br> D. 7 units
Vera_Pavlovna [14]

Answer:

Option A

Step-by-step explanation:

According to the distance formula , for any 2 points P & Q whose coordinates are (x¹ , y¹) and (x² , y²) respectively. So ,

PQ = \sqrt{(x^{2} - x^{1} )^{2} + (y^{2} - y^{1})^{2} }

NOTE = HERE x² , y² DOESN'T MEAN THE SQUARES OF x & y . THEY ARE JUST COORDINATES.

According to the question ,

Coordinate of C = (2 , -1)

Coordinate of D = (5 , 3)

Using distance formula ,

CD = \sqrt{(5-2)^{2} + (3 -(-1))^{2} }

=> CD = \sqrt{3^{2} + 4^{2} } = \sqrt{9 + 16} = \sqrt{25} = 5

5 0
3 years ago
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