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insens350 [35]
3 years ago
6

About how much more grape juice and orange juice is used in the punch

Mathematics
1 answer:
agasfer [191]3 years ago
6 0

3 1/3 --> 3 8/24 --> 80/24

6 1/2 --> 6 12/24 --> 156/24

4 1/8 --> 4 3/24 --> 99/24

1 1/4 --> 1 6/24 --> 30/24

About how much more grape juice <u><em>and </em></u>orange juice is used in the punch

80/24+156/24 = 59/6 or 236/24

99/24+30/24= 43/8 or 129/24

236/24-129/24= 107/24 cups OR 4.458 cups OR 4 11/24 cups

About how much more grape juice <u><em>than </em></u>orange juice is used in the punch

3 1/3 --> 3 8/24 --> 80/24

6 1/2 --> 6 12/24 --> 156/24

approximately -3

hope this helps!

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The sum of 5 consecutive integers is 65. what are those integers?
Alexus [3.1K]

The numbers are: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11

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3 years ago
Solve the system <br> 2x+2y+z=-2 <br> -x-2y+2z=-5<br> 2x+4y+z=0
drek231 [11]

The values of (x,y,z) are (3,-1,-2) , if the given are equations 2x+2y+z=- 2,-x-2y+2z=-5 and 2x+4y+z=0.

Step-by-step explanation:

The given is,

                          2x+2y+z=- 2.......................................(1)

                         -x-2y+2z=-5......................................(2)

                            2x+4y+z=0.........................................(3)

Step:1

           Equation (2) is multiplied by -1            ( Eqn(2) × -1 )

                                         x+2y-2z=5.............................(4)

          Subtract the equation (1) and (4)

                                        2x+2y+z=- 2

                                         x+2y-2z=5

                 ( - )

           (2x-x)+(2y-2y)+(z+2z)=(-2-5)

                                                  x+3z=-7......................(5)

Step:2

          Equation (2) is multiplied by -2                 ( Eqn(2) × -2)

                                        2x+4y-4z=10........................(6)

         Subtract equation (6) and (3),                  

                                        2x+4y-4z=10

                                         2x+4y+z=0

                   ( - )

       (2x-2x)+(4y-4y)+(-4z-z)= (10-0)

                                                     -5z=10

                                                         z = - \frac{10}{5}

                                                         z = -2

         From the equation (5),

                                                  x+3z=-7  

                                          x+(3)(-2)=-7

                                                           x = -7+6

                                                            x = -1

         From equation (1),

                                            2x+2y+z=- 2

          Substitute x and z values,

                               (2)(-1)+2y+(-2)=-2

                                                     2y - 4=2

                                                           2y=4-2

                                                           2y=2

                                                            y=\frac{2}{2}

                                                             y = 1

Step:3

                Check for solution,

                                  -x-2y+2z=-5

                Substitute x,y and z values,

               -(-1)-(2)(1)+(2)(-2)=-5

                                         1-2-4=-5

                                                    -5 = -5

Result:

              The values of (x,y,z) are (3,-1,-2) , if the given are equations 2x+2y+z=- 2,-x-2y+2z=-5 and 2x+4y+z=0.

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