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dlinn [17]
3 years ago
6

Tell whether each statement about the expression 5y + 9 is True or False.

Mathematics
1 answer:
pishuonlain [190]3 years ago
5 0

Answer:

False.

Step-by-step explanation:

The number 5 IS a coefficient because it is the first number in the expression.

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Please Help!!!! Solve For L
Sonja [21]
<h3>Given :</h3>

  • \tt B = L - L a f

<h3>To Find :</h3>

  • L = ?

<h3>Solution :</h3>

\tt B = L - L a f

By taking L common from \tt (L - L a f), we get :

\tt : \implies B = L(1 - a f)

\tt : \implies \dfrac{B}{(1 - a f)} = L

\tt : \implies L = \dfrac{B}{1 - a f}

Hence, value of \tt L = \dfrac{B}{1 - a f}

4 0
3 years ago
Read 2 more answers
Carys is checking her tax bill for the last year .the tax rates were as follows: no tax on the first 11000 of earnings .earnings
faust18 [17]

Answer:

$7,440.

Step-by-step explanation:

We have been given the tax rates as follows:

$0-$11,000 = No tax.

$11,000-$43,000 = 20%.

$43,000-$150,000 = 40%.

Earnings over $150,000 = 45%.

Since last year Carys earned $45,600, so we will have to find the tax paid by her for 11,000-43,000 at rate of 20%, then the tax for amount over 43,000 at the rate of 40%.

\text{The amount of tax paid by Carys for 11000-43000}=\frac{20}{100}\times (43,000-11,000)  

\text{The amount of tax paid by Carys for 11000-43000}=0.20\times (32,000)

\text{The amount of tax paid by Carys for 11000-43000}=6400

\text{The amount of tax paid by Carys for the amount over 43000}=\frac{40}{100}\times (45,600-43,000)

\text{The amount of tax paid by Carys for the amount over 43000}=0.40\times (2600)

\text{The amount of tax paid by Carys for the amount over 43000}=1040

\text{The total amount of tax paid by Carys}=6400+1040

\text{The total amount of tax paid by Carys}=7440

Therefore, Carys paid an amount of $7,440 in tax.

6 0
3 years ago
Read 2 more answers
0.355555555... as a fraction
Pie

Answer:

7111/2000...........

5 0
2 years ago
Find the product of (2x + 5y)2. (2 points)
nasty-shy [4]
4x + 10y

Hope it’s right
Best luck with your studying
6 0
2 years ago
Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1
belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

            F(x) = \int\limits^a_b {f(x)} \, dx

By using integration formula

\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

 \int\limits^6_^-6} (x^{5}  + 8 x^{4}  + 2 x^{2}  + 5 x + 15) )dx

<em>On integration , we get</em>

=   (\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}

F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)

= (\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))

After simplification and cancellation we get

 =  \frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6

on calculation , we get

= \frac{124,416}{5} + \frac{864}{3} + 180

On L.C.M  15

= \frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}

= 25 351.2 units²

<u><em>Conclusion</em></u>:-

<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>

6 0
2 years ago
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